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gregori [183]
1 year ago
13

Determine the type of triangle that is drawn below. R 34° 4 T 1019 5.6 3.22 45° S

Mathematics
1 answer:
iren [92.7K]1 year ago
3 0

Answer:

Scalene Obtuse Triangle

Explanation:

Given the triangle in the attached image.

Classifying based on sides;

The triangle is a Scalene Triangle because all the sides of the triangle are different in sizes, no two sides are equal.

Also classifying based on angles;

The triangle ia an Obtuse Triangle because it has one of its angle greater than 90 degrees, it consist of one obtuse angle.

Therefore, combining the two classifications, The triangle is a Scalene Obtuse Triangle.

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An angle measures 114° less than the measure of its supplementary angle. What is the measure of each angle?
dezoksy [38]

Answer:

66°

Step-by-step explanation:

x+114°=180°

x+114°-114°=180°-114°

x=66°

3 0
2 years ago
A man gathers nuts in a forest. Each time he finds a nut, there is a 20% chance it is a pecan and a 35% chance it is a walnut.
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Either a pecan or walnut means you add the probabilities together

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2 years ago
Prove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero. Fill in the miss
mario62 [17]

Answer:

We conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

  • \frac{ad+cb}{bd}       ∵ b≠0, d≠0, so bd≠0

Step-by-step explanation:

Let a, b, c, and d are integers.

Let a/b and c/d are two rational numbers and b≠0, d≠0

Proving that the sum of two rational numbers is rational.

\frac{a}{b}+\frac{c}{d}

As the least common multiplier of b, d: bd

Adjusting fractions based on the LCM

\frac{a}{b}+\frac{c}{d}=\frac{ad}{bd}+\frac{cb}{db}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

          =\frac{ad+cb}{bd}

As b≠0, d≠0, so bd≠0

Therefore, we conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

  • \frac{ad+cb}{bd}       ∵ b≠0, d≠0, so bd≠0
3 0
3 years ago
Solve for y2. d = y2- y1
kvasek [131]
D=y2-y1
D+y1= y2-y1+y1 add y1 to both sides to cancel it out.

D+y1=y2 that drops -y1 for the right side but the left remains.

And that's your answer.
8 0
3 years ago
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