Answer:
r = 2
Step-by-step explanation:
= 4r-4
square root both sides
r = 
4r-4
r = 2r-2
2r-r = 2
r = 2
The solution of the given equation is -6 and 1.
<h3>What is Quadratic Equation?</h3>
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
Here, given equation:
(x+2)(x+3) = 12
x(x+3)+2(x+3) = 12
x² + 3x + 2x + 6 = 12
x² + 5x + 6 - 12 = 0
x² + 5x - 6 = 0
x² + 6x - x - 6 = 0
x(x+6) -1(x+6) = 0
(x+6)(x-1) = 0
Now, x + 6 = 0 or x - 1 = 0
x = -6 or x = 1
Thus, the solution of the given equation is -6 and 1.
Learn more about Quadratic Equation from:
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Answer:
D
Triangle Midsegment
5
10
Step-by-step explanation:
Got it right on the assignment on EDG2020 :)
1 /5 = 0 . 2
45 * . 2 = 9
Hope this helped :)
Answer:
See below.
Step-by-step explanation:
It transforms to the Pythagoras theorem.
c^2 = a^2 + b^2 - 2ab cos C
If C = 90, cos C = zero so the last term disappears.
c^2 = a^2 + b^2 - 2ab * 0
c^2 = a^2 + b^2.
