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11 months ago

How many time does 8 go into 448

Mathematics

2 answers:

Andrej [43]11 months ago

7 0

Answer: 56 times

Step-by-step explanation:

Vilka [71]11 months ago

4 0

8 goes into 448 56 times.

8 x 56 = 448

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What does a discrete quantitative variable mean?

andrey2020 [161]

Answer:

A discrete quantitative variable is one that can only take specific numeric values (rather than any value in an interval)

Step-by-step explanation:

A discrete quantitative variable is one that can only take specific numeric values (rather than any value in an interval), but those numeric values have a clear quantitative interpretation. Examples of discrete quantitative variables are number of needle punctures, number of pregnancies and number of hospitalizations.

7 0

2 years ago

AAAAAAAAA help please

Firdavs [7]

The answer is the first one BC ~ CD
Ok done. Thank to me:>

4 0

2 years ago

I have some questions that need to be answered fast. 1. 42/j = 35/55

Novay_Z [31]

$\frac{42}{j} = \frac{35}{55}$

to solve for j first you need to cross multiply;

j × 35 = 42 × 55

35j = 2,310

j = 2,310 ÷ 35 (did the inverse operation)

j = 66

Hope that helps :D

6 0

2 years ago

Given a function <img src="https://tex.z-dn.net/?f=f%28x%29%3D3x%5E4-5x%5E2%2B2x-3" id="TexFormula1" title="f(x)=3x^4-5x^2+2x-3"

Levart [38]

Answer:

$\huge\boxed{f(-1) = -7}$

Step-by-step explanation:

In order to solve for this function, we need to substitute in our value of x inside to find f(x). Since we are trying to evalue f(-1), we will substitute -1 in as x to our equation.

$f(-1) = 3(-1)^4 - 5(-1)^2 + 2(-1) - 3$

Now we can solve for the function by multiplying/subtracting/adding our known values.

Starting with the first term to the last term:

$3(-1)^4 = 3$

WAIT! How is this possible? $-1^4 = -1$ (according to my calculator), and $3 \cdot -1 = -3$ , not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use $-2^2$ as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

- Brackets

- Exponents

- Multiplication/Division

- Addition/Subtraction

Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than being "-2 squared" - it's "the negative of of 2 squared."

Tying this back into our problem, the squared method would only be true if it looks like $-1^4$ . However, since we're substituting in -1, it looks like $(-1)^4$ , so the expression reads out as "-1 to the fourth."