Let his total money be x.
He spent (3/7)*x of his money.
He gave 1/4(x-3/7x) to his sister.
which is : (1/4)*(4/7)*x = (1/7)*x
Now,
How much money he have in the beginning =
(3/7)*x+(1/7)*x+120=x
(4/7)*x+120=x
120=x-(4/7)*x
120=(3/7)*x
x=120*7/3 [cross multiplication]
x=280.
So, Alex had $280 in the beginning.
Hello from MrBillDoesMath!
Answer:
1/ 91.4
Discussion:
Evaluate 1/ ( 3x^3 + 5.2y) when x = 3, y = 2.
1/ (3 (3)^3 + 5.2(2)) =
1/ ( 3 * 27 + 10.4) =
1/ ( 81 + 10.4) =
1/ (91.4) =
.0109 (approx)
Thank you,
MrB
Answer: well this is hard
Step-by-step explanation:
First of all you’re adding 7Y and you’re getting -8 and for subtracting you subtract 5why and you’re getting negative one so technically you’re getting different answers?
