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stealth61 [152]
3 years ago
14

Which is greater,forty-five hundredths or six tenths? Explain.

Mathematics
2 answers:
MAXImum [283]3 years ago
8 0
I think it would be six tenths because another way to write 6 tenths is 60 hundreths. So, you'd compare 60 hundreths and 45 hundreths, and since 60 is bigger than 40, it would be six tenths....I'm not really good at explaining things, but, I hope this helped.
ipn [44]3 years ago
5 0
6 tenths becaause would you rather want 45 cents or 60 cents
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y(1) = Ae^k = 0.945A \implies e^k = 0.945 \implies k = \ln 0.945

\text{Then } Ae^{(\ln 0.945)t} = \frac{1}{2}A\ \Leftrightarrow\ \ln e^{(\ln 0.945)t} = \ln \frac{1}{2}\ \Leftrightarrow\  ( \ln 0.945) t = \ln \frac{1}{2} \Leftrightarrow \\ \\
t = - \frac{\ln 5}{\ln 0.945} \approx 12.25 \text{ years}

(b)
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3 years ago
What is 4/9 equivalent to ?
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The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar
mafiozo [28]

Answer:

Ratio = \frac{R^2 - r^2 }{ r^2}

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

The area of a sector is:

Area = \frac{\theta}{360}\pi r^2

For the inner circle

r \to radius

The sector of the inner circle has the following area

A_1 = \frac{\theta}{360}\pi r^2

For the whole circle

R \to Radius

The sector of the outer sector has the following area

A_2 = \frac{\theta}{360}\pi (R^2 - r^2)

So, the ratio of the outer sector to the inner sector is:

Ratio = A_2 : A_1

Ratio = \frac{\theta}{360}\pi (R^2 - r^2) : \frac{\theta}{360}\pi r^2

Cancel out common factor

Ratio = R^2 - r^2 : r^2

Express as fraction

Ratio = \frac{R^2 - r^2 }{ r^2}

6 0
2 years ago
What is the sum or difference? 3x^8 + 7x^8
posledela

Answer:

10x^8 is the sum

Step-by-step explanation:

7 0
3 years ago
Help me with this problem
ryzh [129]

Answer:

angle 1 = angle 3

= 180°-136°

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