Answer:
IDENTICAL
Explanation:
<em>Daughter cells are cells that result from the division of a single parent cell. They are produced by the division processes of mitosis and meiosis. At the completion of the mitotic cell cycle, a single cell divides forming two daughter cells. A parent cell undergoing meiosis produces four daughter cells.</em>
Answer:
it is a failure of tolerance (self-tolerance) and specificity (recognition)
Explanation:
Type 1 diabetes is a chronic disease caused by the selective destruction of β cells that are involved in the production of insulin in the pancreas. Type 1 diabetes can be classified into two types: Type 1A diabetes (the immune form of the disease) and Type 1B diabetes (the non-immune form of the disease). Type 1A diabetes is considered an autoimmune disorder where immune responses against pathogens suffer a failure of tolerance to antigens in the β-cells of the pancreatic islets. Thus, Type 1A diabetes is characterized by the process of recognition of β-cell antigens (autoantigens) by the immune system. This disease is often caused by genetic factors associated with mutations in the human leukocyte antigen (HLA) class II region located on chromosome 6.
Answer:
The way to find a codon is by arranging the sequence of nitrogenous bases of the mRNA in groups of three, the triplets. Once the codon is found, the anticodon corresponds to a complementary triplet to that codon.
Explanation:
Codon corresponds to a triplet of mRNA nitrogen bases encoding an amino acid. Anticodon is responsible for carrying amino acids to the ribosome, according to the information of the mRNA, and the sequence of its triple must be complementary to that of the codon mRNA.
If, for example, a codon of the mRNA is AUG, its anticodon of the tRNA must be UAC, that is, complementary. Then, for the indicated exercises:
<u>Exercise 1:</u>
- DNA ATACGAAATCGCGATCGCGGCGATTCGG
- mRNA UAUGCUUUAGCGCUAGCGCCGCUAAGCC
- CODON UAU|GCU|UUA|GCG|CUA|GCG|CCG|CUA|AGC|C-
- AntiCODON AUA|CGA|AAU|CGC|GAU|CGC|GGC|GAU|UCG|G-
- Amino acid Tyr|Ala|Leu|Ala|Leu|Ala|Pro|Leu|Ser
<u>Exercise 2: </u>
- DNA TTTACGGCCATCAGGCAATACTGG
- mRNA AAAUGCCGGUAGUCCGUUAUGACC
- CODON AAA|UGC|CGG|UAG|UCC|GUU|AUG|ACC
- AntiCODON UUU|ACG|GCC|AUC|AGG|CAA|UAC|UGG
- Amino acid Lys|Cys|Arg|Stop|Ser|Val|Met|Thr
Answer:80
Explanation:
the answer is 80 because you just do 705-625= 80
