What is the diameter of a circle with an area of 78.5 squared cm
1 answer:
Given:
The area of the circle = 78.5 squared cm
We know that:

so,
![\begin{gathered} \pi\cdot r^2=78.5 \\ \\ r^2=\frac{78.5}{\pi}=\frac{78.5}{3.14}=25 \\ \\ r=\sqrt[]{25}=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cpi%5Ccdot%20r%5E2%3D78.5%20%5C%5C%20%20%5C%5C%20r%5E2%3D%5Cfrac%7B78.5%7D%7B%5Cpi%7D%3D%5Cfrac%7B78.5%7D%7B3.14%7D%3D25%20%5C%5C%20%20%5C%5C%20r%3D%5Csqrt%5B%5D%7B25%7D%3D5%20%5Cend%7Bgathered%7D)
so, the radius of the circle = r = 5 cm
The diameter of the circle is two times the radius
So, the answer will be Diameter = 2 * 5 = 10 cm
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