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BabaBlast [244]
1 year ago
11

Identify p, q, and r if necessary. Then translate each argument to symbals and use a truth table to decide if the argument is va

lid or invalid.

Mathematics
1 answer:
anzhelika [568]1 year ago
5 0
Answer:

Explanation:

Let p denote the statement "It snows", and q denote tthe statement "I can go snowboarding"

The we need to draw a table for

(p => q)v(-p => q)

p q -p -q p=>q -p => -q (p => q)v(-p => q)

T T F F T T T

T F F T F T T

F T T F T F T

F F T T T T T

The argument is valid, since the last column has truth all through.

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Find the perimeter of the triangle with vertices (−2,2), (0,4), and (1,−2).
balu736 [363]
By distance formula 
the perimeter would be
the sum of 5+root5+root8

please thank me and mark as the brainiest answer
3 0
4 years ago
Find p (2) when p = 15 (prob & stats)
irinina [24]

Answer:

find  p (2) when p = 15 (prob & stats)

the answer is  30

Step-by-step explanation:

since p is given to be 15 then p(2) will be expressed as p x 2

15 x 2

=30

6 0
3 years ago
A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot
Olegator [25]

Answer:

The ratio of the drag coefficients \dfrac{F_m}{F_p} is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, c_{m} = The drag coefficient of the prototype, c_{p}

The medium of the test for the model, \rho_m = The medium of the test for the prototype, \rho_p

The drag force is given as follows;

F_D = C_D \times A \times  \dfrac{\rho \cdot V^2}{2}

We have;

L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m

Therefore;

\dfrac{L_p}{L_m}  = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2

\dfrac{L_p}{L_m}  =\dfrac{17}{1}

\therefore \dfrac{L_p}{L_m}  = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{c_p \times A_p \times  \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times  \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}

\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3

\dfrac{F_m}{F_p}  = \left( \left\dfrac{1}{17} \right)^3= (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients \dfrac{F_m}{F_p} ≈ 0.0002.

5 0
3 years ago
Please help. Due at 11:59 and I have so much to do
igomit [66]

Mean:24.98

Median:3

Mode:3

Sorry I'm not an expert ;-; but if it's correct, can u mark me as brainiest?

3 0
4 years ago
PLRASE HELP ASAPPPPPPP​
garik1379 [7]
Answer: c. H

Explanation: 37+45+35+29+52=198
198/5=39.6

Hope this helped! :)
3 0
3 years ago
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