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BabaBlast [244]
1 year ago
11

Identify p, q, and r if necessary. Then translate each argument to symbals and use a truth table to decide if the argument is va

lid or invalid.

Mathematics
1 answer:
anzhelika [568]1 year ago
5 0
Answer:

Explanation:

Let p denote the statement "It snows", and q denote tthe statement "I can go snowboarding"

The we need to draw a table for

(p => q)v(-p => q)

p q -p -q p=>q -p => -q (p => q)v(-p => q)

T T F F T T T

T F F T F T T

F T T F T F T

F F T T T T T

The argument is valid, since the last column has truth all through.

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Julie drove 495 miles in 9 hours what was julies average speed in miles per hour
Tpy6a [65]

Answer:

55 miles per hour

Step-by-step explanation:

We just divide 495 by 9 which equals 55 m/h

8 0
2 years ago
Simplify the expression:<br> -6(1.4 - r)=
Vitek1552 [10]

Answer:

6r-8.4

Step-by-step explanation:

-6(1.4-r)

Use the distibutivve property to multiply -6 by 1.4 - r

-8.4 +6r

Then move over 6r to the front

6r-8.4

6 0
2 years ago
Read 2 more answers
A college library has five copies of a certain text on reserve. Two copies (1 and 2) are first printings, and the other three (3
sleet_krkn [62]

Answer:

B) Outcomes in A = {3, 4, 5} .

C) Outcomes in B = {5, 15, 25, 125, 215} .

D) Outcomes in C = {3, 4, 5, 23, 24, 25} .

Step-by-step explanation:

We are given that a college library has five copies of a certain text on reserve. From which two copies (1 and 2) are of first printings, and the other three (3, 4, and 5) are of second printings.

Also, it is stated that a student will stop examining the books only when a second printing has been selected.

A) The outcomes in S are :

      <u> Number of outcomes</u>                                 <u>Selection of Outcomes</u>

                  1                                                                          3

                  2                                                                         4

                  3                                                                          5

                  4                                                                         13

                  5                                                                         14

                  6                                                                         15

                  7                                                                         23

                  8                                                                         24

                  9                                                                         25

                 10                                                                         123

                 11                                                                          124

                 12                                                                          125

                 13                                                                          213

                 14                                                                           214

                 15                                                                            215

Here outcome 123 means 1st copy of first printing is examined then 2nd copy of first printing is examined and then 3rd copy of second printing is examined and then the student stops.

B) <em>A denote the event that exactly one book must be examined.</em>

 So, the outcomes in A will be outcome number 1, 2 and 3 corresponding to selection 3, 4 and 5 of second printing because in these outcomes only one book is examined.

Hence, outcomes in A = {3, 4, 5} .

C) <em>B be the event that book 5 is the one selected</em>. It means all those outcomes in which book 5 was last examined. So, the outcomes in B will be outcome number 3, 6, 9, 12, 15 corresponding to selection 5, 15, 25, 125, 215

Hence, outcomes in B = {5, 15, 25, 125, 215} .

D) <em>C be the event that book 1 is not examined</em> which is outcome number 1, 2, 3, 7, 8, 9 corresponding to selection 3, 4, 5, 23, 24, 25 .

Hence, outcomes in C = {3, 4, 5, 23, 24, 25} .

6 0
3 years ago
What is the product of (5 m Superscript negative 2 Baseline) (2 m Superscript negative 3 Baseline)?
uysha [10]

Answer:

C ) 10/m⁵

Step-by-step explanation:

In this question, we have to find the product of two terms

First term = 5 m⁻²

Second term = 2 m⁻³

Product of both terms = (5 m⁻²) · (2 m⁻³)

The simple way of calculating product of these two term which involves constants as well as variable is that we multiply the constants together:

5·2 = 10

And we multiply the variables. According to the rules of multiplication, when 2 same constants or variables are multiplied, we can just add their powers to get the result.

(m⁻²) · (m⁻³) = m⁻²⁻³ = m⁻⁵

The product of both terms can be written as:

(product of constants)(product of variables) = (10)(m⁻⁵) = 10/m⁵

So the correct option is C

7 0
3 years ago
Read 2 more answers
Rearrange, P=2l+2w solve for w.
Gennadij [26K]
P= 2l+2w

P-2l= 2w

1/2P -l= w

Rearrange into standard form.

w= 1/2P -l
8 0
3 years ago
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