Answer:
both linear and nonlinear
Answer:
x = 4, y = 2
Step-by-step explanation:
Start by multiplying the first equation by 2:
2x + 2y = 12 --> 4x + 4y = 24
Subtract the second from the first:
4x + 4y = 24
- 5x + 4y = 28
4x - 5x = -x
4y = 4y = 0
24 - 28 = -4
so you end with -x + 0 = -4
Solve for x to get x = 4
Plug x = 4 back into 2x + 2y = 12 to find y.
2(4) + 2y = 12
8 + 2y = 12
2y = 4
y = 2
Multiply 65 and .4 which will give you the answer of 26.
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
(x - 4)² + y² = 16
Step 02:
polar form:
x = r cos (θ)
y = r sin (θ)
(r cos (θ) - 4 )² + (r sin (θ))² = 16
(r cos θ - 4)² + r² sin² θ = 16
r (r - 8 cos (θ)) = 0
r = 8 cos θ
The answer is:
r = 8 cos θ
