Question

If f(x)=x2-2x and g(x)=6x=4, for which value of x does (f+g)(x)=0

Answer 1

X = -2
hope it helps (: 

Answer 2

Answer:  The required value of x is - 2.

Step-by-step explanation:  We are given the following two functions :

$f(x)=x^2-2x,~~~~~g(x)=6x+4.$

We are to find the value of x for which (f + g)(x) = 0.

We know that for any two functions p(x) and q(x), the following property holds true :

$(p+q)(x)=p(x)+q(x).$

We have

$(f+g)(x)=0\\\\\Rightarrow f(x)+g(x)=0\\\\\Rightarrow x^2-2x+6x+4=0\\\\\Rightarrow x^2+4x+4=0\\\\\Rightarrow (x+2)^2=0\\\\\Rightarrow x+2=0,~~~x+2=0\\\\\Rightarrow x=-2,~-2.$

Thus, the required value of x is - 2.