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3 years ago

Quadratic vertex Y=-1×2+2×+3

Mathematics

1 answer:

Ronch [10]3 years ago

8 0

Answer:

the question isnt clear, i dont get the equation either, but i made assumptions, i think u want it in vertex form so here the vertext form

f(x)=1*(x+2)^2-3

$f(x) = 1 \times {(x + 2)}^{2} - 3$

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Hey can someone tutor me on math till 12? or till i finsh

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2 years ago

What is the probability against a spinners landing o a green section if the spinner had 15 sections & 3 of them are green an

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The percentage would be 67%

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3 years ago

Pls help ASAP I will give brainleist answer

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6 3/10 pounds

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2 years ago

Read 2 more answers

the graduate record exam (gre) is a standardized test which serves as an admission requirement for many graduate schools, and ha

True [87]

main answer : the normal distribution of given graduate record exam is 1,A(1)=0.3413

supporting answer:Because of its flared shape, a graphical representation of a normal distribution is sometimes referred to as a bell curve. The precise shape varies depending on the population distribution, but the peak is always in the middle and the curve is always symmetrical. The mean, mode, and median of a normal distribution are all the same.

body of the answer: given that x₁=mean+standard deviation

given mean₁=462

standard deviation =119

x₁=462+119=581

z₁=581-462/119=1

A(1)=0.3413

given mean₂=584

standard deviation=151

x₂=584+151

=735

z₂=735-584/151

A(1)=0.3413

final answer:there fore both scores are normal

to learn more about normal distribution link

brainly.com/question/23418254#:~:text=Expert%2DVerified%20Answer&text=Most%20values%20are%20close%20to%20the%20mean%20value.,curve%20called%20the%20normal%20curve.

#SPJ4

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1 year ago

In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin

Mademuasel [1]

Answer: $7\frac{5}{7}$ unit and 18 unit

Step-by-step explanation:

Let ABCD is a trapezoid where AB and CD are the bases. ( In which AB is greatest base which shown in below figure)

AD and BC are the legs of the trapezoid ABCD.

Now, we have ( According to the question ),

AB = 18 unit, BC = 7 unit, AD = 3 unit and DC = 11 unit.

Here the leg AD extends from point D.

Similarly leg BC extends from point C.

Let they meet at point P ( shown in below diagram)

Since In triangles PAB and PDC,

∠PDC ≅ ∠PAB ( because DC ║ AB )

And, ∠ PAB ≅ ∠ PBA

∠DPC ≅ ∠ APB ( reflexive)

Therefore, By AAA similarity postulate,

$\triangle PDC \sim \triangle PAB$

Thus, By the definition of similarity,

$\frac{PD}{PA} = \frac{DC}{AB}$

$\frac{PD}{PD+3} = \frac{11}{18}$ ( because PA = PD+DA)

⇒ 18 PD = 11 PD +33

⇒7PD = 33

⇒ PD = 33/7

Again by the definition of similarity,

$\frac{PC}{PB} = \frac{DC}{AB}$

$\frac{PC}{PC+7} = \frac{11}{18}$ ( because PB = PC + CB)

⇒ 18 PC = 11 PD +77

⇒7PC = 77

⇒ PC = 11

Thus, PA = PD+DA = 33/7 + 3 = $7\frac{5}{7}$

And, PB = PC + CB = 11 + 7 = 18

8 0

3 years ago