1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Delvig [45]
3 years ago
11

The cost of a car rental is $30 per day plus $.20 per mile you are on a daily budget of $94 write and solve an inequality to fin

d the greatest distance you can drive each day while staying within your budget
Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0
STEP 1
determine inequality

Car rental= $30 per day
Mileage= $0.20 per mile
m= number miles driven

Add daily rental charge to the quantity of (number of miles driven multiplied by the per mile charge). This has to be less than or equal to the budget of $94 a day.

$30+ ($0.20 * m) ≤ $94
$30 + $0.20m ≤ $94


STEP 2
solve

$30 + $0.20m ≤ $94
subtract 30 from both sides

0.20m ≤ 64
divide both sides by 0.20

m ≤ 320 mile limit


ANSWER:
Inequality: $30 + $0.20m ≤ $94
320 miles is the daily mileage limit and can be driven daily to stay under (or equal to) the $94 daily budget.

Hope this helps! :)
You might be interested in
Please help please anyone please help me with this please please help
77julia77 [94]

Answer:

plleaseeeeeeeeeeeeeeeeeeeeeeeee eeeeeeeeee

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Translate the triangle left 1 units and up 5 units. What are the coordinates of point C after the translation?
Step2247 [10]

Answer:

b++nfr

Step-by-step explanation:

jjkiki

5 0
3 years ago
Read 2 more answers
What is the fact family for 1,2,3​
irina1246 [14]
1+2=3, 3-1=2, and 3-2=1


6 0
2 years ago
Arthur is testing the effectiveness of a new acne medication. There are 100 people with acne in the study. Forty patients receiv
Rainbow [258]

Answer:

to be honest I'm not sure

7 0
3 years ago
Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,
Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

  • \displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}  }  

In order to use t*, we need to check conditions for using a t-distribution first.

  • Random for both samples -- NOT STATED in the problem ∴ <u><em>proceed with caution</em></u>!
  • Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
  • Normality: CLT is not met; <u>n < 30</u> for both locations A and B ∴ <u><em>proceed with caution</em></u>!

<u>Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.</u>

<u>Solve for t*:</u>

<u></u>

We need the <u>tail area </u>first.

  • \displaystyle \frac{1-.9}{2}= .05

Next we need the <u>degree of freedom</u>.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

  • df for A: 13 - 1 = 12
  • df for B: 18 - 1 = 17
  • df for A - B: |12 - 17| = 5

Use a calculator or a t-table to find the corresponding <u>t-score for df = 5 and tail area = .05</u>.

  • t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

  • \overline {x}_A=39
  • s_A=8
  • n_A=13
  • \overline {x}_B = 55
  • s_B=2
  • n_B=18
  • t^{*}=-2.015

Substitute the variables into the formula: \displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}  }.

  • 39-55 \  \pm \ -2.015 \big{(}\sqrt{\frac{(8)^2}{13} +\frac{(2)^2}{18} } } \ \big{)}

Simplify this expression.

  • -16 \ \pm \ -2.015 (\sqrt{5.1453} \ )
  • -16 \ \pm \ 3.73139

Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

  • (-20.5707,-11.4293)

If we want to <u>interpret</u> the confidence interval of (-20.5707, -11.4293), we can say...

<u><em>We are 90% confident that the interval from -20.5707 to -11.4293 holds the true mean of items sold at locations A and B.</em></u>

5 0
2 years ago
Other questions:
  • You have a can that is in the shape of a cylinder. It has a volume of about 1,726 cubic centimeters. The height of the can is 22
    12·1 answer
  • Find the exact value of sin –255°.
    6·1 answer
  • Could anyone please help?​
    6·2 answers
  • Trapezoid ABCD is graphed in a cordinate plane
    7·1 answer
  • If the expression x-3 has a value of -5, then what is the value of 3x-9
    11·2 answers
  • Log2(y)=3log3(u)<br> log5(y)=2log(u) + 3log5(v)<br> Write y in terms of u and v
    10·1 answer
  • Does anyone know hw to find the zeros of this function <br> h(x)=x2 - 4x + 1
    13·1 answer
  • Please answer number 9 and here is the translation “ Luis already wrote 5 pages of a science report. He plans to write 1 page ev
    9·2 answers
  • PLEASE HELP ⁉️ POR FAVOR SOMEONE IM DESPERATE tHIS IS DUE IN THE mORiNG!
    6·1 answer
  • Rewrite the following in radical form <br> X^-11/3
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!