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Delvig [45]
3 years ago
11

The cost of a car rental is $30 per day plus $.20 per mile you are on a daily budget of $94 write and solve an inequality to fin

d the greatest distance you can drive each day while staying within your budget
Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0
STEP 1
determine inequality

Car rental= $30 per day
Mileage= $0.20 per mile
m= number miles driven

Add daily rental charge to the quantity of (number of miles driven multiplied by the per mile charge). This has to be less than or equal to the budget of $94 a day.

$30+ ($0.20 * m) ≤ $94
$30 + $0.20m ≤ $94


STEP 2
solve

$30 + $0.20m ≤ $94
subtract 30 from both sides

0.20m ≤ 64
divide both sides by 0.20

m ≤ 320 mile limit


ANSWER:
Inequality: $30 + $0.20m ≤ $94
320 miles is the daily mileage limit and can be driven daily to stay under (or equal to) the $94 daily budget.

Hope this helps! :)
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Answer:

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Step-by-step explanation:

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f(g(x)) = (g(x)) -\frac{1}{3}

f(g(x)) = (3x + 1) -\frac{1}{3}

Simplifying, we obtain:

(f o g)(x) = 3x + 1 -\frac{1}{3}\\\\(f o g)(x) = 3x + \frac{2}{3}

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From equation a:
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