2c+8=0
2c=-8
2/2 -8/2
C=-4
Im not exactly sure what the ES O San and 46 is tho
We are given the length of AC and AB to be 20 and 6, respectively, so we can subtract 6 from 20 to find BC to be 14 cm.
The circumference of a circle is equal to
![2 \pi r](https://tex.z-dn.net/?f=2%20%5Cpi%20r)
![C=2 \pi (14) = 28 \pi](https://tex.z-dn.net/?f=C%3D2%20%5Cpi%20%2814%29%20%3D%2028%20%5Cpi%20)
The answer is approximately 87.96 cm
Hit the mirrors and angle it to hit the target the laser will bounce from the mirror to the target
Answer:
use a tape messure and measure it lol sorry i just had to do it
Step-by-step explanation:
Answer:
134.3
Step-by-step explanation:
In
a right triangle, look at sides XW and XZ.
![\frac{XW}{XZ}=\frac{\text{adjacent}}{\text{hypotenuse}}=\cos{82^\circ}\\\\XW=(XZ)\cos{82^\circ}](https://tex.z-dn.net/?f=%5Cfrac%7BXW%7D%7BXZ%7D%3D%5Cfrac%7B%5Ctext%7Badjacent%7D%7D%7B%5Ctext%7Bhypotenuse%7D%7D%3D%5Ccos%7B82%5E%5Ccirc%7D%5C%5C%5C%5CXW%3D%28XZ%29%5Ccos%7B82%5E%5Ccirc%7D)
You now need to find XW.
In
the measure of angle XZY (the one at the top) is 180 - (82 + 67) = 31 degrees.
Using the Law of Sines in triangle XYZ,
![\frac{XZ}{\sin{67^\circ}}=\frac{540}{\sin{31^\circ}}\\\\XZ=\frac{540 \sin{67^\circ}}{\sin{31^\circ}}](https://tex.z-dn.net/?f=%5Cfrac%7BXZ%7D%7B%5Csin%7B67%5E%5Ccirc%7D%7D%3D%5Cfrac%7B540%7D%7B%5Csin%7B31%5E%5Ccirc%7D%7D%5C%5C%5C%5CXZ%3D%5Cfrac%7B540%20%5Csin%7B67%5E%5Ccirc%7D%7D%7B%5Csin%7B31%5E%5Ccirc%7D%7D)
Put that into the equation for XW above...
![XW=\frac{540\sin{67^\circ}\cos{82^\circ}}{\sin{31^\circ}}](https://tex.z-dn.net/?f=XW%3D%5Cfrac%7B540%5Csin%7B67%5E%5Ccirc%7D%5Ccos%7B82%5E%5Ccirc%7D%7D%7B%5Csin%7B31%5E%5Ccirc%7D%7D)
A calculator shows that this is approximately 134.3