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Karolina [17]
1 year ago
7

In planning her retirement liza deposit some money at 4% interest with twice as much deposited at 5% find the amount deposited a

t each rate if the total annual interest income is $1,680
Mathematics
1 answer:
Finger [1]1 year ago
6 0

Answer:

see the attachment

Step-by-step explanation:

side of which is one foot ...

Top answer · 0 votes

The length of a side of a park is 2400 feetA scale drawing is a smaller image of another ... More

18 votes

Answer:Each side length of the park is 2400 feet.

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chubhunter [2.5K]

Answer:

(5 ^{ - 8} )( {5}^{ - 10} )  =  {5}^{ - 18}  = 2.62 \times  {10}^{ - 13}

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a coin will be tossed 10 times. Find the chance that there will be exactly 2 heads among the first five tosses and exactly 4 hea
777dan777 [17]

Answer:

The chance that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses is P=0.0488.

Step-by-step explanation:

To solve this problem we divide the tossing in two: the first 5 tosses and the last 5 tosses.

Both heads and tails have an individual probability p=0.5.

Then, both group of five tosses have the same binomial distribution: n=5, p=0.5.

The probability that k heads are in the sample is:

P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{5}{k}\cdot0.5^k\cdot0.5^{5-k}

Then, the probability that exactly 2 heads are among the first five tosses can be calculated as:

P(x=2)=\dbinom{5}{2}\cdot0.5^{2}\cdot0.5^{3}=10\cdot0.25\cdot0.125=0.3125\\\\\\

For the last five tosses, the probability that are exactly 4 heads is:

P(x=4)=\dbinom{5}{4}\cdot0.5^{4}\cdot0.5^{1}=5\cdot0.0625\cdot0.5=0.1563\\\\\\

Then, the probability that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses can be calculated multypling the probabilities of these two independent events:

P(H_1=2;H_2=4)=P(H_1=2)\cdot P(H_2=4)=0.3125\cdot0.1563=0.0488

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3 years ago
is a diameter of circle K. If tangents to circle K are constructed through points L and J, what relationship would exist between
Svetllana [295]
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