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Anton [14]
4 years ago
6

Please help and show work

Mathematics
1 answer:
MrMuchimi4 years ago
4 0
11. 18=10+x
         x=8
8/4= 2 hours (because there are 8,15 min periods, 4,15 min per 1 hour)

12. 1.44 x 10⁸

13. 2 x 10¹²
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How many solutions does y=3/4x+2 and y=-3/4x+5 have?
Reptile [31]

Answer:

Only one solution

x=1/2

Step-by-step explanation:

Collect like terms.

3/2x=3

Solve for x.

6x=3

x=1/2

5 0
4 years ago
Please help me with this question
vichka [17]
Write the ratio out.

Number of hands Betty won : Number of hands Adam won

5:20

Both can be simplified by the common factor of 5.

1:4 is the solution.

5 0
3 years ago
How many solutions does the system of two equations shown have? <br> y=3(x+4) <br> y=3(x-4)
balu736 [363]
There is no solution. if you are using the two equations to solve for y and x.

you can plug one equations into the other.

substituting one of the y gives...
3(x+4)=3(x-4)
÷ both sides by 3 gives x+4=x-4

get x on one side and numbers on the other
x-x =4+4
and x-x will give you a 0 for the left side
therefore 0 = 4+4.. not true.
7 0
3 years ago
CORRECT THE ERROR
Pachacha [2.7K]
What are the errors
6 0
3 years ago
Verify the identity. 4 csc 2x = 2 csc2x tan x
vlada-n [284]

Step-by-step explanation:

4csc(2x) = 2csc^2(x) tan(x)

We start with Left hand side

We know that csc(x) = 1/ sin(x)

So csc(2x) is replaced by 1/sin(2x)

4 \frac{1}{sin(2x)}

Also we use identity

sin(2x) = 2 sin(x) cos(x)

4 \frac{1}{2sin(x)cos(x)}

4 divide by 2 is 2

Now we multiply top and bottom by sin(x) because we need tan(x) in our answer

2\frac{1*sin(x)}{sin(x)cos(x)*sin(x)}

2\frac{sin(x)}{sin^2(x)cos(x)}

2\frac{1}{sin^2(x)} \frac{sin(x)}{cos(x)}

We know that sinx/ cosx = tan(x)

Also  1/ sin(x)= csc(x)

so it becomes 2csc^2(x) tan(x) , Right hand side

Hence verified



6 0
3 years ago
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