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eimsori [14]
2 years ago
12

Enter the complete ionic equation to show the reaction of aqueous lead(ii) nitrate with aqueous potassium sulfate.

Chemistry
1 answer:
Anna35 [415]2 years ago
6 0

The full ionic equation for the conversion of aqueous lead (II) nitrate to solid lead (II) sulfate and aqueous potassium nitrate is as follows:

<h3>What is ionic equation ?</h3>

PbSO4(s) + 2 K+ + 2 NO3 = Pb2+(aq) + 2 NO3(aq), 2 K+(aq), and SO42(aq) (aq)

Let's look at the molecular formula that results in solid lead (II) sulfate and aqueous potassium nitrate when aqueous lead (II) nitrate and aqueous potassium sulfate interact. This reaction involves two displacements.

 PbSO4(s) + 2 KNO3 = Pb(NO3)2(aq) + K2SO4(aq) (aq)

All ions and molecular species are included in the full ionic equation.

PbSO4(s) + 2 K+ + 2 NO3 = Pb2+(aq) + 2 NO3(aq), 2 K+(aq), and         SO42(aq) (aq)

The full ionic equation for the conversion of aqueous lead (II) nitrate to solid lead (II) sulfate and aqueous potassium nitrate is as follows:

PbSO4(s) + 2 K+ + 2 NO3 = Pb2+(aq) + 2 NO3(aq), 2 K+(aq), and SO42(aq) (aq)

To learn more about ionic equation refer to

brainly.com/question/13879496

#SPJ4

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