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kaheart [24]
3 years ago
10

A tank can hold up to 2500 liters of liquid. The tank initially contains 1000 liters of a brine solution with 50kg of salt. A br

ine solution containing .025 kg/l of salt flows into the tank at a rate of 40 liters per minute and the well mixed solution is pumped out at a rate of 25 liters per minute. At the moment the tank overflows, how much salt is in the solution

Chemistry
1 answer:
Bogdan [553]3 years ago
8 0

Answer:

67.93 kg.

Explanation:

See the attached pictures for detailed explanation.

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As the concentration of a KOH solution increases, the number of moles of HCl needed to neutralize the KOH solution?
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B) increasesAnswer:

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a bowl of cereal is at a temperature of 62 fahrenheit then the bowl of cereal thermal energy decreases as soon as mass or not ch
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<h3>Answer:</h3>

  53 fahrenheit

<h3>Explanation:</h3>

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Determine the percent ionization of a 0.225 M solution of benzoic acid. Express your answer using two significant figures.
Assoli18 [71]

Answer:

1.68% is ionized

Explanation:

The Ka of benzoic acid, C₇H₆O₂, is 6.46x10⁻⁵, the equilibrium in water of this acid is:

C₇H₆O₂(aq) + H₂O(l) ⇄ C₇H₅O₂⁻(aq) + H₃O⁺(aq)

Ka = 6.46x10⁻⁵ = [C₇H₅O₂⁻] [H₃O⁺] / [C₇H₆O₂]

<em>Where [] are concentrations in equilibrium</em>

In equilibrium, some 0.225M of the acid will react producing both C₇H₅O₂⁻ and H₃O⁺, the equilibrium concentrations are:

[C₇H₆O₂] = 0.225-X

[C₇H₅O₂⁻] = X

[H₃O⁺] = X

Replacing:

6.46x10⁻⁵ = [X] [X] / [0.225-X]

1.4535x10⁻⁵ - 6.46x10⁻⁵X = X²

1.4535x10⁻⁵ - 6.46x10⁻⁵X - X² = 0

Solving for X:

X = -0.0038. False solution, there is no negative concentrations.

X = 0.00378M. Right solution.

That means percent ionization (100 times Amount of benzoic acid ionized  over the initial concentration of the acid) is:

0.00378M / 0.225M * 100 =

<h3>1.68% is ionized</h3>
8 0
3 years ago
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