Answer:
Option a.
0.01 mol of CaCl₂ will have the greatest effect on the colligative properties, because it has the biggest i
Explanation:
To determine which of the solute is going to have a greatest effect on colligative properties we have to consider the Van't Hoff factor (i)
These are the colligative properties:
ΔP = P° . Xm . i → Lowering vapor pressure
ΔT = Kb . m . i → Boiling point elevation
ΔT = Kf . m . i → Freezing point depression
π = M . R . T → Osmotic pressure
Van't Hoff factor are the numbers of ions dissolved in the solution. For nonelectrolytes, the i values 1.
CaCl₂ and KNO₃ are two ionic solutes. They dissociate as this:
CaCl₂ → Ca²⁺ + 2Cl⁻
We have 1 mol of Ca²⁺ and 2 chlorides, so 3 moles of ions → i = 3
KNO₃ → K⁺ + NO₃⁻
We have 1 mol of K⁺ and 1 mol of nitrate, so 2 moles of ions → i = 2
Option a, is the best.
Answer:
superstition
Explanation:
Because there is no scientific reason behind it and no connection of it to science.
a. 301 cg
b. 6.2 km
Explanation:
a. knowing that 1 gram (g) is equal to 100 centigrams (cg) we devise the following reasoning:
if 1 g is equal to 100 cg
then 3.01 g are equal to X cg
X = (3.01 × 100) / 1 = 301 cg
b. knowing that 1 kilometer (km) is equal to 1000 meters (m) we devise the following reasoning:
if 1 km is equal to 1000 m
then Y km are equal to 6200 m
Y = (6200 × 1) / 1000 = 6.2 km
Learn more about:
converting units of measurement
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