From Q = mcΔT, we can rearrange the equation to solve for mass, m = Q/cΔT. The specific heat capacity, c, of solid gold is 0.129 J/g °C. I'm assuming that the energy is given in joules, as it's not specified in the question as written.
m = Q/cΔT = (35.73 J)/(0.129 J/g °C)(40.85 °C - 0.85°C)
m = 6.92 g of gold was present
The answer is heart
good luck!
Answer:
Explanation:
Hello,
In this case, since the molarity is computed by:
Whereas the solute is the hydrochloric acid, we compute the corresponding moles with its molar mass (36.45 g/mol):
Next, since the solution contains both HCl and water, we compute the volume in liters by using its density:
Therefore, the molarity turns out:
Regards.
Answer:
23.76g
Explanation:
To solve for the mass of carbon dioxide (CO2), let us first obtain the number of mole of CO2.
From the question, the following were obtained:
V = 8.13L
P = 204kPa = 204000Pa
Recall: 101325Pa = 1atm
204000Pa = 204000/101325 = 2atm
T = 95°C = 95 + 273 = 368K
R = 0.082atm.L/K/mol
n =?
PV = nRT
n = PV /RT
n = 2 x 8.13/ 0.082 x 368
n = 0.54mole
Now let us convert 0.54mole of CO2 to gram. This is illustrated below:
Molar Mass of CO2 = 12 + (16x2) = 12 + 32 = 44g/mol
Number of mole of CO2 = 0.54mole
Mass of CO2 =?
Number of mole = Mass /Molar Mass
Mass = number of mole x molar Mass
Mass of CO2 = 0.54 x 44
Mass of CO2 = 23.76g
Answer:
Formula for effective nuclear charge is as follows. So, for He atom value of S = 0.30 because the electrons are present in 1s orbital. Therefore, calculate the effective nuclear charge for helium as follows. Thus, we can conclude that the effective nuclear charge for helium is 1.7
Explanation:
The effective nuclear charge experienced by a 1s electron in helium is +1.70.
