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antiseptic1488 [7]
1 year ago
6

which classification of money describes money that can be accessed quickly and easily, and includes coins and paper money as wel

l as checks? multiple choice m-1 m-2 m-3 m-4
Computers and Technology
1 answer:
zhenek [66]1 year ago
5 0

Money that can be promptly and easily appraised falls under the M1 Money classification.

<h3>What are broad and narrow money, respectively?</h3>

Broad money typically refers to M2, M3, and/or M4. The most liquid kinds of money, such as currency (banknotes and coins), as well as bank account balances that may be instantly changed into currency or used for cashless transactions, are generally referred to as "narrow money" (overnight deposits, checking accounts).

<h3>Describe Narrow Money.</h3>

All of the actual money that the central bank has falls under the category of "narrow money," which is a subset of the money supply. Demand deposits, money, and other liquid assets are included. In the US, "narrow money" is referred to as M1 (M0 plus demand accounts).

To know more about Money classification visit:-

brainly.com/question/28095328

#SPJ1

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diamong [38]

Answer:

fortnite

Explanation:

fortnite battle royale is an online multiplier game

4 0
3 years ago
In which type of attack do you get malicious code in links from seemingly reliable websites?
natali 33 [55]

I think it is C. cross-site scripting

6 0
3 years ago
Which is true about TCP and UDP? Choose two answers.
vichka [17]

Answer:

TCP is a connection-oriented protocol

UDP does not acknowledge a receipt of data

Explanation:

TCP (Transmission Control Protocol) is a protocol to transfer data, this is one of the most important protocols on the entire internet, this method was implemented from the beginning of the network.

UDP (User Datagram Protocol) this is a protocol faster than TCP because this method doesn't establish a connection to sent data, in this case, always sent data, but TCP is more secure than UDP, and for that UDP is used to transfer music or videos, and TCP websites and database.

UDP doesn't need acknowledgment is done by UDP, is only concerned with speed.

7 0
3 years ago
Create a class called Hokeemon that can be used as a template to create magical creatures called Hokeeemons. Hokeemons can be of
Viefleur [7K]

Answer:

See Explaination

Explanation:

/*****************************************Hokeemon.java********************************/

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

public class Hokeemon {

private String name;

private String type;

private int age;

public Hokeemon(String name, String type, int age) {

super();

this.name = name;

this.type = type;

this.age = age;

}

public Hokeemon() {

this.name = "";

this.type = "";

this.age = 0;

}

public String getName() {

return name;

}

public void setName(String name) {

this.name = name;

}

public String getType() {

return type;

}

public void setType(String type) {

this.type = type;

}

public int getAge() {

return age;

}

public void setAge(int age) {

this.age = age;

}

public String liveIn() {

if (this.type.equalsIgnoreCase("dwarf")) {

return "Mountain";

} else if (this.type.equalsIgnoreCase("elf")) {

return "Dale";

} else if (this.type.equalsIgnoreCase("fairy")) {

return "Forest";

} else {

return "Shire";

}

}

public boolean areFriends(Hokeemon other) {

if (this.type.equalsIgnoreCase(other.type)) {

return true;

} else if ((this.type.equalsIgnoreCase("dwarf") && other.type.equalsIgnoreCase("elf"))

|| (this.type.equalsIgnoreCase("elf") && other.type.equalsIgnoreCase("dwarf"))) {

return true;

} else if ((this.type.equalsIgnoreCase("hobbit") && other.type.equalsIgnoreCase("fairy"))

|| (this.type.equalsIgnoreCase("fairy") && other.type.equalsIgnoreCase("hobbit"))) {

return true;

} else {

return false;

}

}

public static Hokeemon[] getData(String file) {

Hokeemon[] hokeemons = new Hokeemon[8];

int i = 0;

try {

Scanner scan = new Scanner(new File(file));

while (scan.hasNextLine() && i < hokeemons.length) {

String line = scan.nextLine();

String[] data = line.split("\\s+");

String name = data[0];

String type = data[1];

int age = Integer.parseInt(data[2]);

hokeemons[i] = new Hokeemon(name, type, age);

i++;

}

scan.close();

} catch (FileNotFoundException e) {

System.err.println(e);

}

return hokeemons;

}

public static String getBio(Hokeemon[] hokeemons) {

String s = "";

for (Hokeemon hokeemon : hokeemons) {

s += "I am " + hokeemon.getName() + ": Type " + hokeemon.getType() + ": Age=" + hokeemon.getAge()

+ ", I live in " + hokeemon.liveIn() + "\n";

s += "My friends are: ";

for (Hokeemon hokeemon2 : hokeemons) {

if (hokeemon.areFriends(hokeemon2) && !hokeemon.equals(hokeemon2)) {

s += (hokeemon2.getName() + " ");

}

}

s += "\n";

}

return s;

}

atOverride

public String toString() {

return "Name " + name + ": Type " + type + ": Age=" + age + "\n";

}

}

/*******************************HokeemonMain.java**************************/

import java.util.Arrays;

public class HokeemonMain {

public static void main(String[] args) {

Hokeemon[] hokeemons = Hokeemon.getData("data.txt");

System.out.println(Arrays.toString(hokeemons));

System.out.println(Hokeemon.getBio(hokeemons));

}

}

/**********************************data.txt********************/

Noddy Dwarf 4

Legolas Elf 77

Minerva Fairy 33

Samwise Hobbit 24

Merry Hobbit 29

Warhammer Dwarf 87

Ernedyll Elf 19

Frodo Hobbit 18

3 0
3 years ago
Implement function hex2dec that takes a hex number hex_num as a string argument and prints out the corresponding decimal number.
DerKrebs [107]

Answer:

Check the explanation

Explanation:

#include <iostream>

using namespace std;

void hex2dec(string hex_num){

int n = 0;

//Loop through all characters in string

for(int i=0;i<hex_num.size();i++){

//take ith character

char c = hex_num[i];

//Check if c is digit

if(c>='0' && c<='9'){

n = 16*n + (c-48);

}

//Convert c to decimal

else{

n = 16*n + (c-55);

}

}

cout<<hex_num<<" : "<<n<<endl;

}

int main()

{

hex2dec("EF10");

hex2dec("AA");

return 0;

}

The Output can be seen below :

4 0
3 years ago
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