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Likurg_2 [28]
3 years ago
12

Lori Redford, who has been a member of the Project Management group, was recently promoted to manager of the team. She has been

added as a member of the Managers group. Several days after being promoted, Lori needs to have performance reviews with the team she manages but she cannot access the performance management system. As a member of the Managers group, she should have the Allow permission to access this system. What is most likely preventing her from accessing this system
Computers and Technology
1 answer:
Marat540 [252]3 years ago
3 0

Answer:

she is still a member of the Project Management group

Explanation:

The most likely reason for this is that she is still a member of the Project Management group. This would prevent her from accessing the performance management system. The performance management system most likely allows access to the Managers Group but denies access to the Project Management Group. Therefore, since the deny access overrides the allow access, it would ultimately cause Lori to be unable to access the system. In order to fix this, she would simply need to leave the Project Management Group.

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Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3
Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0
3 years ago
A user profile has a login hour restrictions set to. Monday through A user profile has login hour restrictions set to. Monday th
Savatey [412]

Answer:

D

Explanation:

The user will be logged out and any unsaved work-in-progress will be lost.

In a computer program if a user has login hour restrictions this means that such a user will not be able to continue with his/her work when its past the restriction time.

Therefore at 5.01 pm the user will be logged out and any unsaved work-in-progress will be lost.

8 0
3 years ago
You create a database that stores data in tables that consist of rows and columns. each row has a primary key, and each column h
jeyben [28]
The answer is a relational database.

A data model in database management system consists of rules that define how the DB organizes data. Today, a relational database is widely used. It is a collection of data items organized as a set of formally described tables from which data can be accessed in many different ways.



3 0
3 years ago
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Describe the procedure for creating a table or spreadsheet in a presentation slide.
vodomira [7]

Answer:

Select the slide that you want to insert a table on.On the Insert tab, in the Tables group, click Table, and then click Excel Spreadsheet.To add text to a table cell, click the cell, and then enter your text

Explanation:

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Is “Annabelle” a true story? I mean it is fiction right?
Julli [10]
Annabelle is indeed a true story making it fiction
5 0
3 years ago
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