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Aleks [24]
2 years ago
4

ECCEName:2-4 Additional PracticeScan forMultimediaIn 1-10, write the ordered pair for each point.1. A2.B10173. C4.D8АF65. E6. F4

77. G8. HBN9.110.)10-620046810-20-2H-4In 11-16, graph and label each point.11. U(-5, -3)12. V-9,3)C6D13. W(3,8)14. X(8,3)COE1015. Y(6, -6)16. Z(-5,0)
Mathematics
1 answer:
Softa [21]2 years ago
3 0

This is a cartesian coordinate system and every point has it's coordinate on the horizontal (x) axis and vertical (y) axis. The x coordinate is written and followed by the y coordinate.

1) (-8,6) | This corresponds to a point that is -8 units off the x axis and 6 off the y axis.

2) (2,2) | This corresponds to a point that is 2 units off the x-axis and 2 off the y axis.

3) (-3,-6) | This corresponds to a point that is -3 units off the x-axis and -6 off the y axis.

4) (8,-8) | This corresponds to a point that is 8 units off the x-axis and -8 off the y axis.

5) (-7,-9)

6) (6,6)

7) (-6,3)

8) (4,-4)

9) (9,0)

10) (0,4)

It'll be observed that the -x coordinates always lie on the left of the axes while x-coordinates lie on the right.

It'll be observed that the -y coordinates always lie below the axes while x-coordinates lie on the top.

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Leona [35]

Answer:

Step-by-step explanation:

7

6 0
3 years ago
3/4ths multiplied by x equals 4 7/8ths what is x
alexandr402 [8]

Answer:

x=13/2

Step-by-step explanation:

3/4x=4 7/8

x= 4 7/8 divided by 3/4

x=13/2

check

3/4*13/2=39/8

=4 7/8

7 0
4 years ago
In ΔABC, AC = BC, CD ⊥ AB with D ∈ AB , AB = 4 in, and CD = sqrt3 in. Find AC.
amid [387]
Check the picture below.

segments AC and BC are equal, that means that ABC is an isosceles triangle, with twin sides.  Now the twin sides make twin angles on the opposite side, namely the angles at A and B are twins.

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an angle bisector like CD with twin angles on each side, will cut AB in two equal halves, therefore, if AB = 4, then AD = 2 and DB = 2.

8 0
3 years ago
Choose true if the event is independent or false if the event is not independent.
Mila [183]
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3 0
3 years ago
PLEASE HELP SMART PEOPLE! <br>This is add/subtract polynomials. <br>h(x)+g(x)<br>h(x)=6x^2+4x^4+7x​
luda_lava [24]

Given,

h(x) =  {6x}^{2}  +  {4x}^{4}  + 7x

g( x) =  {6x}^{2}  - 4x +  {3x}^{4}

Therefore,

h(x) + g(x)

( {6x}^{2}  +  {4x}^{4}  + 7x) + ({6x}^{2}  - 4x +  {3x}^{4})

{6x}^{2}  +  {4x}^{4}  + 7x + {6x}^{2}  - 4x +  {3x}^{4}

(4 {x}^{4}  + 3 {x}^{4} ) + ( {6x}^{2}  +  {6x}^{2} ) + (7x - 4x)

{7x}^{4}  +  {12x}^{2}  + 3x

4 0
3 years ago
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