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Fed [463]
3 years ago
6

Please help me!!!! No idea how to do this one.

Mathematics
1 answer:
Volgvan3 years ago
3 0
Class A - IQ1 - 76 - IQ3 - 81 - IQR - 5
Class B - IQ1 - 75 - IQ3 - 82 - IQR - 7
Class B is more variated than Class A.
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The velocity v and maximum height h of the water being pumped into the air are related by the equation v=\sqrt(2gh) where g is t
Whitepunk [10]

The velocity v and maximum height h of the water being pumped into the air are related by the equation

v= \sqrt{2gh}

where g = 32

(a) To find the equation that will give the maximum height of the water , solve the equation for h

v= \sqrt{2gh}

Take square root on both sides

v^2 = 2gh

Divide by 2g on both sides

\frac{v^2}{2g} = h

So maximum height of the water h = \frac{v^2}{2g}

(b) Maximum height h= 80

velocity v= 75 ft/sec

Given g = 32

h = \frac{v^2}{2g}

h = \frac{75^2}{2*32}

h= 87.89 ft

The pump withe the velocity of 75 ft/sec reaches the maximum height of 87.89 feet. 87.86 is greater than the maximum height 80 feet.

So the pump will meet the fire department needs.

8 0
3 years ago
Determine the solubility for cuc2o4(s) in pure water. Ksp for is 2. 9 × 10^-8
Elena-2011 [213]

Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.

<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>

The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:

Ksp = [Cu²⁺] [C₂O₄²⁻]

Solving gives:

2.9 x 10⁻⁸ = S x S

S² = 2.9 x 10⁻⁸

S = 1.7 x 10⁻⁴ M

Find out more on solubility at brainly.com/question/23659342.

#SPJ1

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2 years ago
Brainliest if correct
Westkost [7]

Answer:

2y+6

Step-by-step explanation:

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4 0
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it would be 0.254.

you have to convery the millimeter to meters

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3 years ago
I NEED THIS ASAP!!!! PLZ HELP!!!!! 25 POINTS!!!
Solnce55 [7]

Answer: B

Step-by-step explanation:

6 0
2 years ago
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