The velocity v and maximum height h of the water being pumped into the air are related by the equation
v= 
where g = 32
(a) To find the equation that will give the maximum height of the water , solve the equation for h
v= 
Take square root on both sides
= 2gh
Divide by 2g on both sides
= h
So maximum height of the water h = 
(b) Maximum height h= 80
velocity v= 75 ft/sec
Given g = 32
h = 
h = 
h= 87.89 ft
The pump withe the velocity of 75 ft/sec reaches the maximum height of 87.89 feet. 87.86 is greater than the maximum height 80 feet.
So the pump will meet the fire department needs.
Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
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Answer:
2y+6
Step-by-step explanation:
distribute
it would be 0.254.
you have to convery the millimeter to meters
Answer: B
Step-by-step explanation: