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sergey [27]
2 years ago
11

PLEASE HELP SMART PEOPLE! This is add/subtract polynomials. h(x)+g(x)h(x)=6x^2+4x^4+7x​

Mathematics
1 answer:
luda_lava [24]2 years ago
4 0

Given,

h(x) =  {6x}^{2}  +  {4x}^{4}  + 7x

g( x) =  {6x}^{2}  - 4x +  {3x}^{4}

Therefore,

h(x) + g(x)

( {6x}^{2}  +  {4x}^{4}  + 7x) + ({6x}^{2}  - 4x +  {3x}^{4})

{6x}^{2}  +  {4x}^{4}  + 7x + {6x}^{2}  - 4x +  {3x}^{4}

(4 {x}^{4}  + 3 {x}^{4} ) + ( {6x}^{2}  +  {6x}^{2} ) + (7x - 4x)

{7x}^{4}  +  {12x}^{2}  + 3x

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Which value of n makes the following equation true?
grin007 [14]

Answer: d. 512

Step-by-step explanation:

You need to remember that:

(\sqrt[3]{x})^3=x

Then, given the equation:

\sqrt[3]{n}=8

You can find the value of "n" that make the equation true, by solving for "n".

So, to solve for "n", you need to raise both side of the equation to power 3. Therefore, you get:

 \sqrt[3]{n}=8

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Then, the value of "n" that makes the equation \sqrt[3]{n}=8 true is: 512 (You can observe that this matches with the option d).

6 0
4 years ago
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s344n2d4d5 [400]

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6 0
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