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elixir [45]
2 years ago
6

Please help me out ! I don't understand how to get this

Mathematics
1 answer:
Scilla [17]2 years ago
6 0

The value of angle x is 53° for the given triangle.

<h3>What is angle?</h3>

An angle is the formed when two straight lines meet at one point, it is denoted by θ.

In the given isosceles triangle,

one angle is 74°,

Since, two sides of the isosceles triangle are equal, so the corresponding angles will be equal to x.

The sum of angles of a triangle = 180°

x + x + 74 = 180

2x = 106

x = 53

The required value of angle x is 53°.

To learn more about Angle on:

brainly.com/question/28451077

#SPJ1

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Answer:

0.1065

Step-by-step explanation:

Given :2(3x+1)^5=8

Solution :

2(3x+1)^5=8

(3x+1)^5=4

Taking natural log both sides

ln[(3x+1)^5]=ln 4

Property : ln (a^b)=bln(a)

5 ln(3x+1)=ln 4

ln(3x+1)=\frac{1}{5} ln 4

ln(3x+1)=\frac{1}{5} (1.3863)

ln(3x+1)=0.27726

e^{ln(3x+1)}=e^{0.27726}

Property : e^{ln x}=x

3x+1=1.3195

3x=0.3195

x=\frac{0.3195}{3}

x=0.1065

Hence the value of x is 0.1065

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\large{ \tt{❋ \: EXPLANATION}} :

  • The formula to find out the volume of a rectangular prism is V = l × b × h where V is the volume , l = length , b = breadth & h = height.

  • We're provided the figure of trapezium in the second attachment. The formula to fInd out the area of trapezium is A = \tt{ \frac{1}{2} h(a + b)} where a and b are the opposite parallel sides and h be the height of a trapezium.

\large{ \tt{❃ \: SOLUTION}} :

  • In the first picture , we're provided - Length ( l ) = \frac{7}{4} cm , breadth ( b ) = \frac{3}{2} cm and height ( h ) = \frac{1}{2} cm. Now, plug these known values and them find out the volume of given rectangular prism.

\large{ \tt{❁ \: VOLUME \: OF \: RECTANGULAR \: PRISM \: ( \: V \: ) = l \times b  \times h}}

\large{ {⟶ \:  \frac{7}{4}  \times  \frac{3}{2}  \times  \frac{1}{2} }}

  • To multiply one fraction by another , multiply the numerators for the numerator and multiply the denominator for its denominator and reduce the fraction obtained after multiplication into lowest term if possible.

\large{  ⟶ \frac{7 \times 3 \times 1}{4 \times 2 \times 2} }

\large{⟶ \frac{21}{16}  \tt{ {cm}^{3} }}

  • Hence , the volume is \boxed{ \frac{21}{16}   } cubic centimetres.

--------------------------------

  • In the second attachment , we're provided - 6ft and 7 ft are the opposite parallel sides and 3 ft is the height of the given trapezium.

\large{ \tt{✺ \: AREA \: OF \: A \: TRAPEZIUM =  \frac{1}{2} h(a + b)}}

\large{ ⟶ \frac{1}{2}  \times 3(6 + 7)}

\large{⟶ \:  \frac{1}{2} \times 3 \times 13 }

\large{⟶ \frac{39}{2}  \tt{cm}^{2} }

  • Hence , The area of trapezium is \boxed{ \frac{39}{2}  \tt{cm}^{2} }

And we're done ! ♪

\large{  \# \: \mathfrak{StayInAndExplore \:☂ }}

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