Step-by-step explanation:
Answer:
0.2377 or about a 23.77% chance
Step-by-step explanation:
P(123<X<130) = normalcdf(123,130,130,11) = 0.2377303466 ≈ 0.2377
Therefore, the probability that the next game Victoria bowls, her score will be between 123 and 130 is 0.2377 or about a 23.77% chance
16 n^2 -10n + 129 = 8n^2 -8
We collect the terms:
8n^2 -10n + 137 = 0
The steps for completing the square:
1) Move the "non X" (or "non N") term to the right:
8n^2 -10n = -137
<span>2)<span> Divide the equation by the coefficient of N² which in this case is 8
n^2 -1.2n = </span></span><span><span>-17.125
</span>
3) Take the coefficient of "N"; divide it by 2; square it; add it to both sides of the equation.
-1.2 / 2 = -.6
-.6^2 = .36
</span>
n^2 -1.2n +.36 = <span>-17.125
+.36
Take the square root of both sides:</span>
(n-.6)*(n-.6) = sq root(
<span>
<span>
<span>
-16.765
</span>
</span>
</span>
)
That's about as far as I can go.
Answer:
RD≅ TA
Step-by-step explanation:
RD≅ TA is not true statement as they are not corresponding sides.
