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luda_lava [24]
10 months ago
9

The perimeter of a rectangular metal plate is 15 cm. Find the length of the rectangular plate (in decimals) whose width is 228 c

m. Use estimation in tenths place.

Mathematics
1 answer:
scoray [572]10 months ago
6 0

The Solution.

Representing the problem in a diagram, we have

By formula,

P=2(L+W)

In this case,

P=15\operatorname{cm},L=?,W=\frac{22}{8}cm

Substituting these values in the formula above, we get

15=2(L+\frac{22}{8})

Clearing the bracket, we get

15=2L+(2\times\frac{22}{8})\begin{gathered} 15=2L+\frac{11}{2} \\  \\ 15=2L+5.5 \end{gathered}\begin{gathered} 15-5.5=2L \\ 9.5=2L \end{gathered}

Dividing both sides by 2, we get

L=\frac{9.5}{2}=4.75\approx4.8\operatorname{cm}

Therefore, the correct answer is option C.

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Construction paper cost $0.10 per square inch. How much will Susan spend to make this figure out of construction paper? ​
AfilCa [17]

The will spend $33.60 (option C) to make the figure out of construction paper, if the construction paper cost $0.10 per square inch.

Step-by-step explanation:

The given is,

                 Construction paper cost $0.10 per square inch

                 Pyramid diagram with dimensions

Step:1

               Formula to calculate the area of pyramid,

                            Area, A = lw+l\sqrt{(\frac{w}{2}) ^{2} + h^{2} } +w \sqrt {(\frac {l} {2}) ^{2} + h^{2} }..............(1)

             Where,

                        l - Base length

                      w - Base width

                      h - Height of pyramid

             From given,

                       l = 12 inches

                     w = 12 inches

            For height of pyramid,

             By using Pythagorean theorem,

                                       Hypotenuse^{2} = Base^{2} + Height ^{2}.................(2)

              For right angle triangle,

                                             Base = \frac{12}{2} = 6 inches

              Equation (2) becomes,

                                                  8^{2} = 6^{2} + Height^{2}

                                        Height^{2} = 8^{2} - 6^{2}

                                        Height^{2} = 64 -36 = 28

                                          Height = \sqrt{28}

                                          Height = 5.2915 inches

                    h - 5.2915 inches

                Equation (1) becomes,

                       A = (12)(12)+(12)\sqrt{(\frac{12}{2}) ^{2} + 5.2915^{2} } +(12 )\sqrt {(\frac {12} {2}) ^{2} + 5.2915^{2} }

                          = 144+(12)\sqrt{(36+27.999)} +(12)\sqrt{(36 + 27.999)}    

                          = 144+(12)\sqrt{63.999}+(12)\sqrt{63.999}

                          = 144+(12)(7.9999)+(12)(7.9999)

                          =144+95.999+95.999

                          =335.998      

                          ≅ 336 square inches

                Where,

                         $0.10 per square inch ( from given)

                 Paper cost of total figure = 336 square inches

                                                             = 336 × 0.10

                                                             = $ 33.60

Result:

           The will spend $33.60 to make the figure out of construction paper, if the construction paper cost $0.10 per square inch.

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Six more than the product of 24 and Vidya’s age
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If we use v for Vidya's age, then the expression (24v)+6

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3 years ago
If both sides of a gable roof are the same size, and one side of the roof measures 15'x 36*, how many squares of 16" x 5/2" wood
kogti [31]

Approximately 3 shingles used to cove the area of the roof.

According to the statement

we have to find the number of shingles used to cover the roof.

So, For this purpose, we know that the

one side of the roof measures 15'x 36

And we have given that the both sides of a gable roof are the same size.

So, For this purpose,

The roof is a of a rectangle shape so,

Area of rectangle = 2(L+B)

Then

Area of rectangle = 2(L+B)

Area of rectangle = 2(15+36)

Area of rectangle = 102 ft.

Then

Area of shingles = 2(L+B)

Area of shingles = 2(16+2.5)

Area of shingles = 37

then number of shingles used = 37/102

So, Approximately 3 shingles used to cove the area of the roof.

Learn more about Area here

brainly.com/question/6613758

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4 0
1 year ago
Casey was able to map line segment \overline{UV} UV start overline, U, V, end overline onto line segment \overline{ST} ST start
Aleonysh [2.5K]

Answer:

A.

Step-by-step explanation:

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3 years ago
Name two Acute, Vertical Angles using the figure below."
e-lub [12.9K]

Answer:

EKH and FKG

Step-by-step explanation:

They are both under 90 degrees as shown by angle FKJ, and they are directly opposite of eachother.

7 0
2 years ago
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