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3 years ago

How are the values of the eights related in 880?

1 answer:

7 0

In the number 880, the first eight is ten times that of the second eight. This is the first way in which the 8’s are related to one another. The second way that the two 8’s are related is that is that if the both 8’s change their respective places, then also the number will remain the same. Since in this case the number in the tens place and the hundreds place are same, so interchanging them will not have any effect on the overall number.

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How much is 27 out of 30 as a percent

Musya8 [376]

It’s 90 percent all you have to do it take 100 then divide it by 30 the times that number by 27 and 90 will be your answer

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3 years ago

Which figure shows the correct dimensions of a 1/3 scale drawing of the given figure

Romashka [77]

Answer:

Ok I cannot see the figure but let me explain to you how to do this. If you see the and know the measurements, just divide all the measurements by 3 and draw the figure again. If I have a rectangle with side lengths 12 and 9, and I want to draw a 1/3 scale drawing, I would divide 12/3 = 4 and 9/3 = 3. So your new side-lengths are 4 and 3. I hoped this helped a little!!

Step-by-step explanation:

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3 years ago

Carly buys 3 more band concert tickets than choir concert tickets. Band concert tickets cost $3.50 per ticket. What is the cost

alexira [117]

Answer:

I'm not to sure, but I'll say 10.5

If you multiply 3.50 x 3 you'll get 10.5

If you add you'll get 13.5.

If it's an addition I'll recommend to go with 13.5

If it's a multiplication I'll recommend to go with 10.5

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2 years ago

Type the correct answer in each box. Find the elements of matrix A. help PLS!!

horsena [70]

Answer:

a = 2

b = 11

c = 11

d = -2

Step-by-step explanation:

$\sf \left[\begin{array}{cc}a&b\\c&d \end{array}\right] *\left[\begin{array}{ccc} 22&11&7\\ 6&-9&-15 \end{array}\right] =\left[\begin{array}{ccc} 22a+6b&11a-9b&7a-15b\\22c+6d&11c-9d&7c-15d \end{array}\right]$

$\sf \left[\begin{array}{ccc} 22a+6b&11a-9b&7a-15b\\22c+6d&11c-9d&7c-15d \\ \end{array}\right] =\left[\begin{array}{ccc} 110&-77&-151\\230&139&107 \\ \end{array}\right]$

On comparing to right side, we get,

22a + 6b = 110

Divide the entire equation by 2

11a + 3b = 55 ------------(I)

11a - 9b = -77 -------------(II)

Subtract equation (II) from (I)

11a + 3b = 55

11a - 9b = -77

- + + {Now subtract}

12b = 132

b = 132/12

$\sf \boxed{\bf \ b = 11}$

Substitute the value of b in eqaution (I)

11a + 3*11 = 55

11a + 33 = 55

11a = 55 - 33

11a = 22

a = 22/11

$\sf \boxed{\bf \ a = 2}$

22c + 6d = 230

Divide by 2

11c + 3d = 115 -----------------(III)

11c - 9d = -139 ------------------(IV)

Subtract (IV) from (III)

11c + 3d = 115

11c - 9d = 139

- + -

12d = -24

d = -24/12

$\sf \boxed{\bf \ d = -2}$

Plugin d = - 2 in equation (III)

11c + 3*(-2) = 115

11c - 6 = 115

11c = 115 + 6

11c = 121

c = 121/11

$\sf \boxed{\bf \ c = 11}$

4 0

2 years ago

(50 points and brainliest. PLEASE HELP)The size of a certain cell is 2.5 × 10^–9 m. Another cell is 1.5 × ^times larger. How lar

Sergeeva-Olga [200]

Answer: the answer is 3.75x10^-6m

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers