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Evgen [1.6K]
3 years ago
8

Who is the three president of somalia​

Computers and Technology
2 answers:
mars1129 [50]3 years ago
8 0

Answer:

Siad Baree,Aden Adde and Aden Madobe

Snezhnost [94]3 years ago
3 0

Answer:

Siad Barre

Explanation:

You might be interested in
Why is stranded rather than solid cable used for patch cables? Why is it critical not to score the jacket too deeply when stripp
Serggg [28]

Answer:

The definition of the issues is listed throughout the section down.

Explanation:

  1. Stranded cables are somewhat more compact and can be mounted quickly. Strong cables become rigid in design, and they are not versatile for installation. In comparison with solid connectors, amplification is indeed high.
  2. Unless the innermost layer including its wire is broken as we attempt to connect the cable, it will not function. So, whenever stripping the cables through the walls, it's indeed important not to rank the jack too profoundly.
  3. It would be quick to untwist the cable and then will ensure that perhaps the connection is appropriate for the most widely encountered rj-45 connection whenever the wiring of 0.5 inches becomes coupled up.
  4. If we don't keep the right pin colors in order, the relation won't work. Afterward, when another connexon is broken due to many complications, it would be impossible to figure out the contacts unless the pins coloring are not always in sequence.
  5. The connection pairs can be cut off through 0.5 inches within about therefore the gap within the connector is narrower and the wire would not be correctly attached if we break the cable further. The link is lost and the cable does not run properly.
  6. It is necessary to ensure that perhaps the wires are forced to the end of the platform since the connexon will indeed be broken as well as the connector would not operate unless the wires aren't moved. The wires will fall out of another socket as well.
  7. Before even being incorporated into another crimping unit, it is good to carefully check the connection sequence to ensure that perhaps the wires are to the end since it is impossible to verify the sequence until the wires are attached to something like the connector. Unless the connections are not always in alignment, the link will also not be provided and indeed the wire would not operate correctly, even if the link is provided. Such wires can also be presented to use load barriers, and that it's the simplest operation.
  8. The Durability Tester has been used to determine the hardness between two stages, whereas the connection efficiency is tested using the qualification tester.

8 0
3 years ago
An important principle in information security is the concept of layers of security, which is often referred to as layered secur
Eva8 [605]

Answer:

Available options in question are

  1. a firewall :  
  2. a server
  3. an application
  4. control standard

Answer is : Control Standard. It is not an example of layer of security.

Explanation:

Defense in depth consists of three major domains like physical, technical and administrative. Layered Security will consists of best practices by combining multiple  security methods to mitigate vulnerabilities and attack vectors. It is used to protect resources at different levels.  

  • A firewall is used as layered security measure to secure networks and systems.It is most commonly used security measure for enterprise products.
  • A server is typical example of physical control. In this  it protects actual IT servers, high-end servers, cloud servers and any physical hardware and assets.  
  • An Application can be used an example of Layer security. Applications like Antiviruses, Vulnerability Scanners, Anti Malware software and Web Application firewall gateways are typical examples

Control Standard is not an example of Layered Security.

5 0
3 years ago
You just finished training a decision tree for spam classification, and it is gettingabnormally bad performance on both your tra
strojnjashka [21]

Answer:

Option B is the correct option.

Explanation:

The following answer is true because when the person completed our training of a decision tree and after the following presentation he getting not good working performance on both side i.e., test sets and during the training period. After the training there is no bug on the implementation of the presentation then, he has to increase the rate of the learning.

5 0
3 years ago
1.
Hatshy [7]

Answer:

Hi!

The following Javascript statement compares if num is 2 or 5 and increment num by 1 if true.

if ( num==2 || num==5)  

num = num +1;

Explanation:

The operator == is used to compare if the operands are equal.

The operator || is OR.

  • If at least one of the operands is true then return true.
  • If all operands are false returns false.

if( num==2 || num==5) <em> // if num is equal 2 or if num is equal 5</em>

num = num +1; <em>// adds 1 to num.</em>

8 0
3 years ago
Start with the following Python code. alphabet = "abcdefghijklmnopqrstuvwxyz" test_dups = ["zzz","dog","bookkeeper","subdermatog
trapecia [35]

Answer:

alphabet = "abcdefghijklmnopqrstuvwxyz"

test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]

test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"]

# From Section 11.2 of: # Downey, A. (2015). Think Python: How to think like a computer scientist. Needham, Massachusetts: Green Tree Press.

def histogram(s):

   d = dict()

   for c in s:

       if c not in d:

           d[c] = 1

       else:

           d[c] += 1

   return d

#Part 1 Write a function called has_duplicates that takes a string parameter and returns True if the string has any repeated characters. Otherwise, it should return False.

def has_duplicates(stringP):

   dic = histogram(stringP)

   for key,value in dic.items():

       if value>1:

           return True

   return False

# Implement has_duplicates by creating a histogram using the histogram function above. Write a loop over the strings in the provided test_dups list.

# Print each string in the list and whether or not it has any duplicates based on the return value of has_duplicates for that string.

# For example, the output for "aaa" and "abc" would be the following. aaa has duplicates abc has no duplicates Print a line like one of the above for each of the strings in test_dups.

print("***Implementation of has_duplicates fuction***")

for sTr in test_dups:

   if has_duplicates(sTr):

       print(sTr+": has duplicates")

   else:

       print(sTr+": has no duplicates")

#Part 2 Write a function called missing_letters that takes a string parameter and returns a new string with all the letters of the alphabet that are not in the argument string.

#The letters in the returned string should be in alphabetical order. Your implementation should use a histogram from the histogram function. It should also use the global variable alphabet.

#It should use this global variable directly, not through an argument or a local copy. It should loop over the letters in alphabet to determine which are missing from the input parameter.

#The function missing_letters should combine the list of missing letters into a string and return that string.

def missing_letters(sTr):

   missingLettersList = []

   dic = histogram(sTr)

   for l in alphabet:

       if l not in dic:

           missingLettersList.append(l)

   missingLettersList.sort()

   return "".join(missingLettersList)

#Write a loop over the strings in list test_miss and call missing_letters with each string. Print a line for each string listing the missing letters.

#For example, for the string "aaa", the output should be the following. aaa is missing letters bcdefghijklmnopqrstuvwxyz

#If the string has all the letters in alphabet, the output should say it uses all the letters.

#For example, the output for the string alphabet itself would be the following. abcdefghijklmnopqrstuvwxyz uses all the letters

#Print a line like one of the above for each of the strings in test_miss.

print("\n***Implementation of missing_letters fuction***")

for lTm in test_miss:

   sTr = missing_letters(lTm.replace(" ",""))

   if sTr!="":

       print(lTm+" is missing letters "+sTr)

   else:

       print(lTm +" uses all the letters")

3 0
3 years ago
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