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stira [4]
11 months ago
7

What is 17 x 5.8 SHOW YOUR WORK please send a photo of work by pressing

Mathematics
1 answer:
11Alexandr11 [23.1K]11 months ago
3 0

Answer:

98.6

Step-by-step explanation:

in photo!!

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Evaluate: 2|x-4|+6 for x=2
Lina20 [59]
<h3>Answer:</h3>

10

<h3>Step-by-step explanation:</h3>

2|x -4| +6 \text{ for } x = 2 \\ 2|2 -4| +6 \\ 2|-2| +6 \\ 2(2) +6 \\ 4 +6 \\ 10

6 0
3 years ago
A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the number of cakes sold per
HACTEHA [7]

Answer:

A) Revenue function = R(x) = (580x - 10x²)

Marginal Revenue function = (580 - 20x)

B) Fixed Cost = 900

Marginal Cost function = (300 + 50x)

C) Profit function = P(x) = (-35x² + 280x - 900)

D) The quantity that maximizes profit = 4

Step-by-step explanation:

Given,

The Price function for the cake = p = 580 - 10x

where x = number of cakes sold per day.

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

where x = number of cakes sold per day.

Please note that all the calculations and functions obtained are done on a per day basis.

A) Find the revenue and marginal revenue functions [Hint: revenue is price multiplied by quantity i.e. revenue = price × quantity]

Revenue = R(x) = price × quantity = p × x

= (580 - 10x) × x = (580x - 10x²)

Marginal Revenue = (dR/dx)

= (d/dx) (580x - 10x²)

= (580 - 20x)

B) Find the fixed cost and marginal cost function [Hint: fixed cost does not change with quantity produced]

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

The total cost function is a sum of the fixed cost and the variable cost.

The fixed cost is the unchanging part of the total cost function with changing levels of production (quantity produced), which is the term independent of x.

C(x) = 900 + 300x + 25x²

The only term independent of x is 900.

Hence, the fixed cost = 900

Marginal Cost function = (dC/dx)

= (d/dx) (900 + 300x + 25x²)

= (300 + 50x)

C) Find the profit function [Hint: profit is revenue minus total cost]

Profit = Revenue - Total Cost

Revenue = (580x - 10x²)

Total Cost = (900 + 300x + 25x²)

Profit = P(x)

= (580x - 10x²) - (900 + 300x + 25x²)

= 580x - 10x² - 900 - 300x - 25x²

= 280x - 35x² - 900

= (-35x² + 280x - 900)

D) Find the quantity that maximizes profit

To obtain this, we use differentiation analysis to obtain the maximum point of the Profit function.

At maximum point, (dP/dx) = 0 and (d²P/dx²) < 0

P(x) = (-35x² + 280x - 900)

(dP/dx) = -70x + 280 = 0

70x = 280

x = (280/70) = 4

(d²P/dx²) = -70 < 0

Hence, the point obtained truly corresponds to a maximum point of the profit function, P(x).

This quantity demanded obtained, is the quantity demanded that maximises the Profit function.

Hope this Helps!!!

8 0
3 years ago
Help please!!! I only have 10 minutes!!
goblinko [34]
I think 0.7 would be it
3 0
2 years ago
Read 2 more answers
200m - 100m + 48,250 = 50,250 – 150m
drek231 [11]

200m - 100m + 48,250 = 50,250 - 150m

(Add or subtract common variables)

100m + 48,250 = 50,250 - 150m

(Add 150m to both sides)

250m + 48,250 = 50,250

(Subtract 48,250 to both sides)

250m = 2000

(Divide 250 to both sides to isolate m)

m = 8

5 0
3 years ago
The owner of the Koffee Shop pours the remainder of her old house blend, which is 40 % 40 % Colombian beans, into a 60 60 -pound
maks197457 [2]

Answer:

0.4h ; 60 - h ;18 - 0.3h ; 0.1h + 18

Step-by-step explanation:

Given that:

Old house blend = 40% Columbian beans

New house blend = 30% Columbian beans

h = number of pounds of old house blend

a.) pound of columbian bean in old house blend :

40% of h = 0.4h

b.) pound of new blend poured into the bean:

Size of bin = 60 pound

Size of bin - pound of old house blend

(60 - h)

c. Amount of columbian bean in pound of new house blend :

30% of (60 - h)

0.3 * (60 - h)

18 - 0.3h

D.) Amount of columbian bean in 60 pound bin

(Pound of columbian bean in old house blend + pound of Columbian bean in New house blend)

0.4h + (18 - 0.3h)

0.4h + 18 - 0.3h

0.1h + 18

4 0
3 years ago
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