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svp [43]
10 months ago
7

#1.3 Find the coordinates of the midpoint of the segment with the given endpoints.

Mathematics
1 answer:
tangare [24]10 months ago
5 0
When we are looking for the mid point, we are looking for a point that is an equal distance from point R and S.

Since the x value has no change, we can ignore it.

For the y value, we want to simply find the difference between the points (7 - 1 = 6) and then divide that value by 2 (6 / 2 = 3).

You can then subtract that value from the higher Y value, where you will get 4.

Leaving you with the coordinate (3,4)

Hope this helped. There are definitely more ways you could find to solve this, but this works best for this problem.
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Answer:

The rule for multiplying and dividing rational numbers

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Answer:

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Step-by-step explanation:

<em><u>Given</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em><em> </em><em>the</em><em> </em><em>line</em><em> </em><em>pass</em><em>es</em><em> </em><em>t</em><em>hrough</em><em> </em><em>the</em><em> </em><em>point</em><em> </em><em>(</em><em> </em><em>0</em><em> </em><em>,</em><em> </em><em>2</em><em> </em><em>)</em><em> </em><em>and</em><em> </em><em>the</em><em> </em><em>slope</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>line</em><em> </em><em>is</em><em> </em><em>(</em><em> </em><em>-</em><em>1</em><em>/</em><em>4</em><em> </em><em>)</em><em> </em>

<em>•</em><em> </em><em>Also</em><em>,</em><em> </em><em>to</em><em> </em><em>form</em><em> </em><em>an</em><em> </em><em>eq</em><em>uation</em><em> </em><em>when</em><em> </em><em>a</em><em> </em><em>po</em><em>int</em><em> </em><em>throu</em><em>gh</em><em> </em><em>which</em><em> </em><em>line</em><em> </em><em>passes</em><em> </em><em>and</em><em> </em><em>slope</em><em> </em><em>of</em><em> </em><em>line</em><em> </em><em>is</em><em> </em><em>given</em><em> </em><em>we</em><em> </em><em>use</em><em> </em><em>the</em><em> </em><em>formula</em><em> </em><em>;</em>

<em>(</em><em> </em><em>y</em><em> </em><em>-</em><em> </em><em>y1</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>m</em><em> </em><em>(</em><em> </em><em>x</em><em> </em><em>-</em><em> </em><em>x1</em><em> </em><em>)</em>

<em>Where</em><em> </em><em>,</em><em> </em><em>y</em><em> </em><em>and</em><em> </em><em>x</em><em> </em><em>are</em><em> </em><em>vari</em><em>ables</em><em> </em>

<em>and</em><em> </em><em>(</em><em> </em><em>x1</em><em> </em><em>,</em><em> </em><em>y1 </em><em>)</em><em> </em><em>are</em><em> </em><em>the</em><em> </em><em>po</em><em>ints</em><em> </em><em>through</em><em> </em><em>which</em><em> </em><em>line </em><em>passes</em><em> </em>

<em>also</em><em>,</em><em> </em><em>m</em><em> </em><em>=</em><em> </em><em>slope</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>re</em><em>quired</em><em> </em><em>line</em><em> </em>

<em>Here</em><em> </em><em>,</em><em> </em><em>x1</em><em> </em><em>=</em><em> </em><em>0</em><em> </em><em>,</em><em> </em><em>y1</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>and</em><em> </em><em>m</em><em> </em><em>=</em><em> </em><em>(</em><em> </em><em>-1</em><em>/</em><em>4</em><em> </em><em>)</em><em> </em>

<em>[</em><em> </em><em>Ref</em><em>er to</em><em> the</em><em> attached</em><em> file</em><em> for</em><em> </em><em>furth</em><em>er</em><em> </em><em>process</em><em> </em><em>]</em>

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