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VLD [36.1K]
2 years ago
8

What is the US TREASURY BONDS pretax expected return?

Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
7 0

Answer:

this is the return on an investment that does not include the taxes the investor must pay on this return

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Diviseur de 63 et 67
dybincka [34]

<span>Diviseur de 63 et 67</span>

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<span>0.94029850746</span>

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2 years ago
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You play the following game against your friend. You have 2 urns and 4 balls One of the balls is black and the other 3 are white
Rom4ik [11]

Answer:

Part a: <em>The case in such a way that the chances are minimized so the case is where all the four balls are in 1 of the urns the probability of her winning is least as 0.125.</em>

Part b: <em>The case in such a way that the chances are maximized so the case  where the black ball is in one of the urns and the remaining 3 white balls in the second urn than, the probability of her winning is maximum as 0.5.</em>

Part c: <em>The minimum and maximum probabilities of winning  for n number of balls are  such that </em>

  • <em>when all the n balls are placed in one of the urns the probability of the winning will be least as 1/2n</em>
  • <em>when the black ball is placed in one of the urns and the n-1 white balls are placed in the second urn the probability is maximum, as 0.5</em>

Step-by-step explanation:

Let us suppose there are two urns A and A'. The event of selecting a urn is given as A thus the probability of this is given as

P(A)=P(A')=0.5

Now the probability of finding the black ball is given as

P(B)=P(B∩A)+P(P(B∩A')

P(B)=(P(B|A)P(A))+(P(B|A')P(A'))

Now there can be four cases as follows

Case 1: When all the four balls are in urn A and no ball is in urn A'

so

P(B|A)=0.25 and P(B|A')=0 So the probability of black ball is given as

P(B)=(0.25*0.5)+(0*0.5)

P(B)=0.125;

Case 2: When the black ball is in urn A and 3 white balls are in urn A'

so

P(B|A)=1.0 and P(B|A')=0 So the probability of black ball is given as

P(B)=(1*0.5)+(0*0.5)

P(B)=0.5;

Case 3: When there is 1 black ball  and 1 white ball in urn A and 2 white balls are in urn A'

so

P(B|A)=0.5 and P(B|A')=0 So the probability of black ball is given as

P(B)=(0.5*0.5)+(0*0.5)

P(B)=0.25;

Case 4: When there is 1 black ball  and 2 white balls in urn A and 1 white ball are in urn A'

so

P(B|A)=0.33 and P(B|A')=0 So the probability of black ball is given as

P(B)=(0.33*0.5)+(0*0.5)

P(B)=0.165;

Part a:

<em>As it says the case in such a way that the chances are minimized so the case is case 1 where all the four balls are in 1 of the urns the probability of her winning is least as 0.125.</em>

Part b:

<em>As it says the case in such a way that the chances are maximized so the case is case 2 where the black ball is in one of the urns and the remaining 3 white balls in the second urn than, the probability of her winning is maximum as 0.5.</em>

Part c:

The minimum and maximum probabilities of winning  for n number of balls are  such that

  • when all the n balls are placed in one of the urns the probability of the winning will be least given as

P(B|A)=1/n and P(B|A')=0 So the probability of black ball is given as

P(B)=(1/n*1/2)+(0*0.5)

P(B)=1/2n;

  • when the black ball is placed in one of the urns and the n-1 white balls are placed in the second urn the probability is maximum, equal to calculated above and is given as

P(B|A)=1/1 and P(B|A')=0 So the probability of black ball is given as

P(B)=(1/1*1/2)+(0*0.5)

P(B)=0.5;

5 0
3 years ago
A new online auction site specializes in selling automotive parts for classic cars. The founder of the company believes that the
LenKa [72]

Solution :

a). The required linear regression model is

Price = $-1242.986 + 75.017 \times \text{age of part} + 13.973 \times \text{ number of bidders}$

b). The $\text{p-value}$ for the variable "Age of part" is 0.0000

Since the $\text{p-value}$ is less than 0.05, so it is significant to the model.

The p-value for the variable "Number of bidders" is 0.1940

Since $\text{p-value}$  is not less than $0.05$, so it is significant to the model.

c). We cannot say that model is significant because variable " the number of bidders" is not significant.

But as both variables have positive coefficient so as the variable increases the price received for the item also increased.

7 0
3 years ago
100 possible points!!!!!! and BRAINLIEST to correct answer of this question:
Akimi4 [234]
This should be a rotation!
7 0
3 years ago
12. Elly's credit card record for the last 7 months is below. Based on the information from the table, what will be her new bala
bogdanovich [222]

Answer:

52145.55

Step-by-step explanation:

5 0
3 years ago
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