Question

Im not sure what the answer too this question is i could really use some help

Answer 1

We have to find the probability that a randomly selected a point it falls into the red shaded area:

First, let us find the area of the circle:

$A_c=\pi r^2=\pi(4)^2=16\pi cm^2$

Now, we can calculate the area of the triangle:

$A_t=\frac{b\ast h}{2}=\frac{r\ast r}{2}=\frac{4\ast8}{2}=16cm^2$

Now, the probability is given by:

$P=\frac{A_t}{A_c}$

Replacing:

$P=\frac{16cm^2}{16\pi cm^2}=0.31830$

Multiply the result by 100:

$P\ast100=31.830$

Rounded to the nearest percent P≈32.

Hence, the result is 32%.