Answer:
A. ![p\geq 15](https://tex.z-dn.net/?f=p%5Cgeq%2015)
Step-by-step explanation:
It is A because the puppy is <em>at least </em>15 pounds and it means the puppy could be greater or equal to 15 pounds.
Answer:
Let x represent the first number and let y represent the second number.
Case I
x + y = 85
or, x = 85 - y - - - ( 1 )
Case II
y = 4 + 2x
or, y = 4 + 2( 85 - y )
or, y = 4 + 170 - 2y
or, y+2y = 174
or, 3y = 174
: . y = 58
Putting the va
![\textrm{average speed} = \dfrac{\text{distance}}{\text{time}}](https://tex.z-dn.net/?f=%5Ctextrm%7Baverage%20speed%7D%20%3D%20%5Cdfrac%7B%5Ctext%7Bdistance%7D%7D%7B%5Ctext%7Btime%7D%7D)
![R(h) = \dfrac{D(h)}{T(h)} = \dfrac{-0.5 h + 9.5}{ -5.5 h + 92.5}](https://tex.z-dn.net/?f=R%28h%29%20%3D%20%5Cdfrac%7BD%28h%29%7D%7BT%28h%29%7D%20%3D%20%5Cdfrac%7B-0.5%20h%20%2B%209.5%7D%7B%20-5.5%20h%20%2B%2092.5%7D)
We can multiply top and bottom by -2 to clear the decimals.
![R(h) = \dfrac{ h - 19 }{11h - 185}](https://tex.z-dn.net/?f=R%28h%29%20%3D%20%5Cdfrac%7B%20h%20-%2019%20%7D%7B11h%20-%20185%7D)
No common factors so we stop here.
2^2a^2+b^2
4a^2+b^2
not sure if this is correct but here ya go