What is the mass of 5.7 x 1022 atoms Mn?

Chemistry

1 answer:

Svet_ta [14]1 year ago

6 0

The mass of 5.2 x 10^22 manganese atoms in grams would be 635.784 grams.

What is Avogadro's constant?
Avogadro's number tells us how many particles are in one mole (or mol) of a substance. <u>Electrons</u><u>, molecules, or atoms</u> could be among these particles. Avogadro's number has a value of approximately 6.022140857×10²³ mol⁻¹. Avogadro's number tells us how many particles are in one mole (or mol) of a substance. <u>Electrons, molecules, or atoms </u>could be among these particles. Avogadro's number has a value of approximately 6.022140857×10²³.

Computation of mass
Avogadro calculated that every material had 6.022 x 10^23 atoms per mole.

5.2 x 10^22 atoms of Mn would contain how many moles?
= 6.022 x 10^23 /1 x 5.2 x10^22
=11.58 moles

Mn mass equals 11.58 moles multiplied by 54.9
= 635.784 grams

You may learn more about Avogadro's constant here: brainly.com/question/15989275
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