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mart [117]
3 years ago
12

Density Calculations

Chemistry
1 answer:
kompoz [17]3 years ago
4 0
The density is 10.67 g/cm^3
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How many orbitals does fluorine contain
Nata [24]

Answer:

2

Explanation:

7 0
3 years ago
Read 2 more answers
Question 6: The Ideal Gas Law (7 points) a. What is the mathematical equation for the ideal gas law? Identify each variable and
azamat

The mathematical equation for the ideal gas law is PV = nRT.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

(A)

PV = nRT

The ideal gas equation is formulated as: PV = nRT. In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.

(B)

Where the pressure - P, is in atmospheres (atm) the volume - V, is in liters (L) the moles -n, are in moles (m) and Temperature -T is in Kelvin (K) as in all gas law calculations.

(C)

A. Boyle's law

B. Charles's law

C. Avogadro's law

D. Dalton's law

____ - P_1V_1 = P_2 V_2

____ \frac{V}{T} = k

____ \frac{V_1}{T_1} = \frac{V_2}{T_2}

____ V = kn

____ PV = k

____- P total = P_1 + P_2 + P_3 + ...

<u>Boyle's</u><u> law</u> - P_1V_1 = P_2 V_2

<u>Charles's</u><u> law</u> - \frac{V}{T} = K

<u>Charles's law</u> - \frac{V_1}{T_1} = \frac{V_2}{T_2}

<u>Avogadro's law</u>- V = kn

<u>Boyle's law</u> - PV = k

<u>Dalton's law</u><u> </u>- P total = P_1 + P_2 + P_3 + ...

Learn more about the  ideal gas law here:

brainly.com/question/21353806

#SPJ1

6 0
2 years ago
In 100 grams of sweet peas there are 14.5 carbohydrates,5.7 grams of sugars,5.1 grams of dietary fiber, 5.4 grams of protein and
Serjik [45]
Percent composition is the quantity or number of parts of a component contained in 100 parts of the total.

Given the the total is 100 g, the reported quantities for each component are the same percent.

Then, the percent composition of each as part of the entire sweet peas is:

Carb: 14.5%
Sugar: 5.7%
Diet. fiber: 5.1%
Prot: 5.4%
Fat: 0.4%

The rest to make the 100% is supposed to be water.

You could also find the percent composition in dry basis, which is done in this way (this is not what the question asks but it is good to know it).

Total components without water: 14.5 + 5.7 + 5.1 + 5.4 + 0.4 = 31.1 grams

Now divide each content by the total (31.1) and multiply by 100.

I will do one example:

Carbs: [14.5 / 31.1 ] * 100 = 46.6%

 

6 0
2 years ago
Calculate the ph of a 3.78×10-3 m solution of naf, given that the ka of hf = 6.80 x 10-4 at 25°c.
Fofino [41]
The answer is pH = 7.37.

Solution:
First, we set up an ICE table for the reaction:                                            
                          F- + H2O → HF + OH-
     Initial             0.00378         0        0
     Change        -x                   +x      +x
     Equilibrium   0.00378-x      x        x

We can calculate Kb from the given Ka, since we know that Kw = Ka*Kb = 1.0 x 10^-14 at  25°C:
     Kb = Kw/Ka = 1.0x10^-14 / 6.80x10^-4 = 1.471 x 10^-11
     Kb = 1.471 x 10^-11 = [OH-][HF] / [F-] = (x)(x) / (0.00378-x)

Approximating that x is negligible compared to 0.00378 simplifies the equation to
     1.471x10^-11 = (x)(x)  / 0.00378          
     1.471 x 10-11 = x2 / 0.00378 

Then we solve for x that is also equal to [OH-]:
     x2 = (1.471 x 10^-11)(0.00378)   
     x = sqrt[(1.471 x 10^-11)(0.00378)] = 2.358x10^-7 = [OH-]
in which 0.0000002358 is indeed negligible compared to 0.00378.

We can now calculate for pOH:         
     pOH = -log [OH-] = -log (2.358x10^-7) = 6.63

Therefore, the pH is
     pH = 14 - pOH = 14 - 6.63 = 7.37
4 0
3 years ago
The Wind chill index tells you
balandron [24]
<span>The correct answer is D.how wind and temperature affect your body in winter. Basically, it's how you perceive the cold weather on your skin regardless of what the temperature actually is. It's usually lower and that's why you have forecasts say that it will be for example 0, but it will feel like -5 degrees Celsius.</span><span />
5 0
3 years ago
Read 2 more answers
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