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meriva
3 years ago
12

14. I have an unknown volume of gas at a pressure of 1.2 atm and a temperature of 210 K. If I raise the pressure to 1.9 atm and

decrease the temperature to 200 K, and measure the final volume to be 56 L, what was the initial volume of the gas? *​
Chemistry
1 answer:
Leya [2.2K]3 years ago
6 0

Answer:

The law is given by the following equation: PV = nRT, where P = pressure, V = volume, n = number of moles, R is the universal gas constant, which equals 0.0821 L-atm / mole-K, and T is the temperature in Kelvin.

Explanation:

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When 3.0 grams of H2 is reacted with excess C at constant pressure, the reaction forms CH4 and releases 53.3 kJ of heat. C(s) +
Murrr4er [49]

Answer:

THE ENTHALPY OF REACTION IN KJ/MOL OF CH4 IS 7.07 KJ/MOL.

Explanation:

Mass of H2 = 3 g

Molar mass of H2 = 2 g/mol

Heat released = 53.3 kJ

Equation of the reaction:

C(s) + 2H2(g) -------> CH4(g)

First:

Calculate the number of moles of H2 that was used:

Number of moles = mass / molar mass

Number of moles = 3g / 2g

Number of moles = 1.5 moles

So therefore, when 53.3 kJ of heat was released from the reaction, 1.5 moles of hydrogen was used.

From the equation of the reaction, one mole of carbon reacts with two moles of hydrogen to form one mole of methane.

For 3 g of hydrogen, 1.5 mole of hydrogen is involved.

It means:

1.5 moles of hydrogen reacts with 0.75 moles of carbon and produces 0.75 moles of methane. This is so because the reaction occurs in 1: 2: 1 in respect to carbon, hydrogen and methane respectively.

So we can say that the production of 0.75 mole of methane will evolve 53.3 kJ of heat.

0.75 mole of methane releases 53.3 kJ of heat.

1 mole of methane will release ( 53.3 kJ * 1 / 0.75 )

= 71.0666 kJ of heat

In conclusion, the enthalpy of the reaction in kJ/ mole of CH4 is 71.07 kJ/mol.

7 0
3 years ago
Which list ranks the gasses in the correct order from the
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Answer:

D. chlorine, oxygen, nitrogen, hydrogen.

Explanation:

  • Thomas Graham found that, at a constant  temperature and pressure the rates of effusion  of various gases are inversely proportional to  the square root of their masses.

<em>ν ∝ 1/√M</em>

where ν is the rate of effusion and M is the atomic  or molecular mass of the gas particles.

  • The molecular mass for the listed gases are:

O₂: 32.0 g/mol,

Cl₂: 70.906 g/mol,

N₂: 28.0 g/mol,

H₂: 2.0 g/mol.

  • Hence, the smallest molecular mass of the gas, the fastest rate of effusion.

So, the order from the slowest to the fastest rate of effusion is:

<em>Chlorine, oxygen, nitrogen, hydrogen.</em>

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Answer:

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Explanation:

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