Question

Show where the expression in number 8 would be on a unit circle

Answer 1

Solution

Step 1:

Write the expression

$cos270\text{ }$

Step 2

$\begin{gathered} cos270\text{ = 0} \\ sin270\text{ = -1} \\ (0,\text{ -1\rparen} \end{gathered}$

Question 8 Second part

$\begin{gathered} sin(\frac{16\pi}{3})\text{ = sin960 = sin\lparen960 - 2}\times360)\text{ = sin240} \\ sin(\frac{16\pi}{3})\text{ = }\frac{-\sqrt{3}}{2} \\ cos(\frac{16\pi}{3})\text{ = }\frac{-1}{2} \end{gathered}$$(\frac{-1}{2},\text{ }\frac{-\sqrt{3}}{2})$