Subtract (-9x^2+8x-14) from the sum of (-9x^2-10x) and (3x^2+3x+7)

Mathematics

1 answer:

nalin [4]3 years ago

8 0

Answer:

$3x^2 - 15x + 21\\or\,\,3(x^2 -5x +7)$

Step-by-step explanation:

First we will find sum of $(-9x^2-10x)\,\, and\,\, (3x^2+3x+7)$

Adding the like terms:

$= -9x^2-10x + 3x^2 +3x+7\\= -9x^2+ 3x^2 -10x+3x+7\\= -6x^2 - 7x +7$

Now subtract (-9x^2+8x-14) from (-6x^2 - 7x +7)

$=(-6x^2 - 7x +7) - (-9x^2+8x-14)\\= -6x^2 - 7x +7 +9x^2-8x+14\\= -6x^2 +9x^2 - 7x -8x+7 +14\\= 3x^2 - 15x + 21\\=3(x^2 -5x +7)$

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A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio

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Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

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Comparing this to the desired form, we see that ...

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