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Mariana [72]
1 year ago
10

In each of the following problems, graph the line with the given slope m and y-intercept b.

Mathematics
1 answer:
Doss [256]1 year ago
4 0

Take into account that in general, a linear function can be written as follow:

y=mx+b

where m is the slope of the line and b the y-coordinate of the y-intercept.

In this case, you have that m=1/5 and b=-3, then, the line equation is:

y=-\frac{1}{5}x-3

In order to graph the line, proceed as follow:

Use two values of x to replace into the equation for y, for instance, use 0 and 5:

\begin{gathered} y=\frac{1}{5}(0)-3=-3 \\ y=\frac{1}{5}(5)-3=1-3=-2 \end{gathered}

The previous results mean that (0,-3) and (5,-2) are two points on the line.

Place the previous points on the coordinate system, and draw a straight line which crosses these points:

The red line is the graph of the given function.

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Answer:

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Step-by-step explanation:

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3 0
4 years ago
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lorasvet [3.4K]

Answer:

11x^(2) - 3

Step-by-step explanation:

Remove the parentheses: (a)=a

=5x^2-7x+10+7x^2-11-x^2+7x-2

Group the like terms:

=5x^2+7x^2-x^2-7x+7x+10-11-2

Add the similar elements : 5x^2+7x^2-x^2=11x^2

=11x^2-7x+7x+10-11-2

Continue to add similar elements: -7x+7x=0

=11x^2+10-11-2

Then add or subtract the numbers:  10-11-2=-3

<u>FINAL ANSWER</u>:= <em>11x^(2)-3</em>

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Step-by-step explanation:

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Step-by-step explanation:

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