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Blizzard [7]
1 year ago
10

Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.Josiah has punch c

ards for his favorite tea house and his favorite coffee shop. He currently has 2 punches on the tea punch card and 11 punches on the coffee punch card. Given his regular routine, he consistently earns 7 new punches per week on the tea punch card and 4 on the coffee punch card. Before too long, Josiah will have the same number of punches on each card. How long will that take? How many punches will Josiah have on each card?
Mathematics
1 answer:
love history [14]1 year ago
6 0

Let x be the number of weeks; therefore, the two linear equations are

\begin{gathered} T=2+7x \\ \text{and} \\ C=11+4x \end{gathered}

Where T stands for the punches on the tea punch card and C for the punches on the coffee punch card.

Solving by substitution. Set T=C, then

\begin{gathered} T=C \\ \Rightarrow2+7x=11+4x \\ \Rightarrow3x=9 \\ \Rightarrow x=\frac{9}{3}=3 \\ \Rightarrow x=3 \end{gathered}

Thus, substitute the value of x=3 into the first equation,

\begin{gathered} x=3 \\ \Rightarrow T=2+7\cdot3=23 \\ \Rightarrow T=23 \end{gathered}

Thus, after 3 weeks, Josiah will have the same number of punches on each card, and he will have 23 punches on each card.

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The critical value is the z-score right at the edge of the rejection region option (A) is correct.

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The z-score is right at the edge of the rejection region.

As we know, the rejection zone is the area in which we have sufficient data to reject the null hypothesis if our test statistic falls within it.

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8 0
2 years ago
What are the solutions of x^2-2x+5=0
sweet [91]

The solution of x^{2}-2 x+5=0 are 1 + 2i and 1 – 2i

<u>Solution:</u>

Given, equation is x^{2}-2 x+5=0

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  --- (1)

<em><u>Let us determine the nature of roots:</u></em>

Here in x^{2}-2 x+5=0 a = 1 ; b = -2 ; c = 5

b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16

Since b^2 - 4ac < 0 , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}

On solving we get,

x=\frac{2 \pm \sqrt{4-20}}{2}

x=\frac{2 \pm \sqrt{-16}}{2}

x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}

we know that square root of -1 is "i" which is a complex number

\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

6 0
3 years ago
9+3v is greater than or equal to 6
kondaur [170]

Answer:

If you take it in terms of integers,

9+3v may or may not be greater or equal to 6. It depends on the value of the variable you put in.

For eg:- if you substitute the value for v as 2 then 9+3x2=15 which is greater than 6 but if you put in -1 for v then you will get 9+3x(-1)=6


8 0
3 years ago
Which set of ordered pairs represents a function? (1 point) {(0, 1), (1, 3), (1, 5), (2, 8)} {(0, 0), (1, 2), (2, 6), (2, 8)} {(
Aleonysh [2.5K]

Answer:

{(0, 2), (1, 4), (2, 6), (3, 6)}

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Hey! can u help me with this?! 6 divided by 3/5 in fraction form!?!?!!?
frutty [35]

Answer:

10/1

Step-by-step explanation:

You do

6÷ 3/5

Flip the 3/5 then multiply

6 ° 5/3

Reduce the numbers with the greatest common factor 3

So 2•5

And that's 10

4 0
3 years ago
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