Imagine that we cut the cone in half with a vertical plane. In this plane we'd see points a, b and c. We need to find the measure of angle bca, and then double that angle, to obtain the answer to this problem.
Note that tan (angle bca) = opp / adj = 2 / 6, or 1/3, or 0.333...
Working backwards to find angle bca, we use the inverse tangent function:
arctan 0.3333.. = approx. 0.322 radians, or 18.435 degrees.
Doubling that gives us the measurement of the angle formed between the line segments: 2(18.435 deg) = 36.9 degrees, approximately.
The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
P.E = mgh = 120N
Step-by-step explanation:
v² = u² - 2as
At the top, the velocity is = 0
0² = 4² - 2 x 10 x s
4² = 20s
s = 16/20
s = 0.8metres.
It rose only 0.8metres.
Therefore P.E = 15 x 10 x 0.8
:. P.E = 15 * 8
:. P.E = 120N
Answer:
Step-by-step explanation:205
Answer:
C11= 1
C12=0
C21=0
C22=1
Step-by-step explanation:
Just took the the assignment
