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erik [133]
1 year ago
14

Find the equation of the line that passes through (-1,-3) and is perpendicular to 2 y = x − 3 . Leave your answer in the form y

= m x + c
Mathematics
1 answer:
Taya2010 [7]1 year ago
7 0

Answer:

Remember that the slope of perpendicular lines are negative reciprocals of each other.Step-by-step explanation:y = 1 - 2x     the slope is -2     the value of the x term.So the slope of the new line using point (- 1, 2)  is  1/2.Now use y = mx + b where y = -1, x = 2, and m = 1/2 .y = mx + b-1 = 1/2(2) + b                solve for "b", the y-intersect-1 =  1 + b-2 = bThe line that is perpendicular to y = 1 - 2x  is  y = 1/2x - 2

Step-by-step explanation:

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Given two vectors A=2i+3j+4k,B=i-2j+3k find the magnitude and direction of sum<br>(physics question)
Law Incorporation [45]

Answer:

Magnitude =\sqrt{59} \\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}}

Step-by-step explanation:

A=2i+3j+4k

B=i-2j+3k

Sum of the vectors:

A + B = 2i+3j+4k + i-2j+3k = 3i + j + 7k

Magnitude =\sqrt{3^2 + 1^2+ 7^2} \\\\Magnitude =\sqrt{9+1+49} \\\\Magnitude =\sqrt{59}

Direction of the sum of the vectors:

\widehat{A + B} =\frac{\overrightarrow{A + B}}{Magnitude\: of \:\overrightarrow{A + B}} \\\\\widehat{A + B} =\frac{3i + j + 7k}{\sqrt {59}} \\\\\widehat{A + B} =\frac{3}{\sqrt {59}} i +\frac{1}{\sqrt {59}} j+\frac{7}{\sqrt {59}} k\\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}} \\\\

3 0
3 years ago
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T is equal to -1.
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Can you help me with this question?
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You take the square root of 81 to get 9. Notice how 9^2 = 9*9 = 81. So if you're not familiar with square roots, then think backwards in a sense to get the answer.
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Step-by-step explanation:

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