The volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)
<h3>How to determine the volume?</h3>
The complete question is added as an attachment
From the attached image, we have:
Length = 12 - 2x
Width = 7 - 2x
Height = x
The volume is calculated as:
Volume = Length * Width * Height
Substitute the known values in the above equation
Volume = (12 - 2x) * (7 - 2x) * x
This gives
Volume = x(12 - 2x)(7 - 2x)
Hence, the volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)
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Answer:
2/3 , 13/18, 7/9 , 5/6 (least to greatest order)
Step-by-step explanation:
1. You need to convert all the fractions into decimal form .
2. 7/9.00 = 0.78 (rounded)
3. 13/18.00 = 0.72
4. 5/6.00 = 0.83
5 . 2/3.00= 0.67 (rounded)
Let L = lengthLet W = width Length is 5 yd less than twice the width ==> L = 2*W - 5 Area is 52 yd^2 ==> 52 = L*W Substitute the value for L from the 1st equation into the 2nd equation
52 = (2*W - 5) * W52 = 2*W^2 - 5*W0 = 2*W^2 - 5*W - 52 0 = (2W - 13)*(W + 4) 2W - 13 = 0 or W + 4 = 0W = 13/2 or W = -4 Width cannot be negative so discard W = -4 W = 13/2 ==> L = 2*(13/2) - 5 = 13 - 5 = 8 So the width is 13/2 yards and the length is 8 yards Check: 2*(13/2) - 5 = 13 - 5 = 8 (13/2)*8 = 4*13 = 52 yd^2
