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Lapatulllka [165]
3 years ago
15

Name two integers whose product is negative.

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
3 0
You know that one integer is a negative integer, as the product is negative- and if the sum is zero, then the absolute value of the two integers are equal. Thus, the integers are +/- sqrt(36). or +/- 6.

Example: 6 and -6

Your welcome.
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What is the factorization of 729^15+1000?
igomit [66]

Answer:

The factorization of 729x^{15} +1000 is (9x^{5} +10)(81x^{10} -90x^{5} +100)

Step-by-step explanation:

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Let's solve the factorization of 729x^{15} +1000 by using the <em>sum and difference of cubes </em>factorization.

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\sqrt[3]{729x^{15}} =9x^{5}

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So, we got that

729x^{15} +1000=(9x^{5})^{3} + (10)^{3} which has the form of (a^{3} +b^{3} ) which means is a <em>sum of cubes.</em>

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(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})

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(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)

.

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