Question

Need to find the equation for the line with the given properties. Express your answer using either the general form or the slope-intercept form of the equation of a line. Slope=1/3, containing the point (-3,3)

Answer 1

To answer this question we will use the following slope-point formula for the equation of a line:

$y-y_1=m(x-x_1)\text{.}$

Therefore, the equation of the line that has a slope of 1/3 and passes through the point (-3,3) is:

$y-3=\frac{1}{3}(x-(-3))\text{.}$

Simplifying the above equation we get:

$\begin{gathered} y-3=\frac{1}{3}(x+3), \\ y-3=\frac{1}{3}x+1. \end{gathered}$

Adding 3 to the above equation we get:

$\begin{gathered} y-3+3=\frac{1}{3}x+1+3, \\ y=\frac{1}{3}x+4. \end{gathered}$

Answer:

$y=\frac{1}{3}x+4.$