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LUCKY_DIMON [66]
1 year ago
6

An animal shelter has 8 puppies. If the puppies are 32% of the total dog and cat population, how many dogs and cats are in the a

nimal shelter?
Mathematics
1 answer:
r-ruslan [8.4K]1 year ago
7 0

Answer:

25

Step-by-step explanation:

32/100=8/x

cross multiply

32x=100(8)

32x=800

/32. /32

x=25

hopes this helps please mark brainliest

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26

Step-by-step explanation:

Pythagorean Theorem and Radius used

24^2 + 10^2 = 676

\sqrt{676}=26

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Step-by-step explanation:

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Doss [256]

Answer:

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Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

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but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
4 years ago
What is (6x+4) - (4x+2)
Nana76 [90]

Answer:

x = -1

Step-by-step explanation:

1. Simplifying

6x + 4 = 4x + 2

2. Reorder the terms

4 + 6x = 4x + 2 to 4 + 6x = 2 + 4x

3. Solving

4 + 6x = 2 + 4x

4. Solving for variable 'x'.

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4 + 6x + -4x = 2 + 4x + -4x

5. Combine like terms: 6x + -4x = 2x

4 + 2x = 2 + 4x + -4x

6. Combine like terms: 4x + -4x = 0

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7. Add '-4' to each side of the equation.

4 + -4 + 2x = 2 + -4

8. Combine like terms: 4 + -4 = 0

0 + 2x = 2 + -4

2x = 2 + -4

9. Combine like terms: 2 + -4 = -2

2x = -2

10. Divide each side by '2'.

x = -1

11. Simplifying

x = -1

4 0
3 years ago
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