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Helen [10]
1 year ago
10

The cost C (in dollars) of producing x DVD players is represented by C = 4.5x2. How many DVD players are produced if the cost is

$544.50 (I recommend looking at the problem through the picture. Question number 13 last question in photo provided)

Mathematics
1 answer:
lisabon 2012 [21]1 year ago
3 0

Given the following equation representing the cost of producing DVD Players:

\text{ C = 4.5x}^2

Let's determine the number of DVD players produced if the cost is $544.50

\text{ C = 4.5x}^2\text{ \$544.50 = 4.5x}^2\text{ }\frac{\text{\$544.50}}{\text{ 4.5}}\text{ = }\frac{\text{4.5x}^2}{\text{ 4.5}}\text{ 121 = x}^2\text{ }\sqrt{\text{121}}\text{ = }\sqrt{\text{x}^2}\text{ 11 = x}

Therefore, it'll cost $544.50 to produce 11 DVD Players.

The answer is 11.

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Mary buys a 10-meter spool of thread for sewing. She uses 210 centimeters. How much is left on the spool in centimeters?
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100 cm = 1 meter

210 cm = 2.1 meters (multiply both sides by 2.1)

Mary uses 2.1 meters of thread so far, meaning she has 10-2.1 = 7.9 meters left

7.9 meters = (7.9 m)*(100 cm/1 m) = 790 cm

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Alternate route:

10 meters = (10 m)*(100 cm/1 m) = 1000 cm

Mary uses 210 cm out of 1000 cm total, so she has 1000-210 = 790 cm left.

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<h3>Answer: 790 cm</h3>
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Nate made 8 loaves of bread on Monday and 10 more on Tuesday. He gave an equal number to each of his 9 neighbors. How many loave
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3 years ago
A textbook search committee is considering
lora16 [44]

Number of ways to select 3 books from 13 books for adoption is 286 .

<u>Step-by-step explanation:</u>

A Permutation is an ordered Combination. When the order does matter it is a Permutation. There are basically two types of permutation:

  • Repetition is Allowed: such as the lock above. It could be "333".
  • No Repetition: for example the first three people in a running race. You can't be first and second.

Formula is given by:

nC_r= \frac{n!}{r! (n-r)!} , where n is the number of things to choose from,  and we choose r of them,  no repetitions,  order matters. Here , n=13 , r=3.

⇒ 13C_3 = \frac{13!}{3!(13-3)!}

⇒ 13C_3 = \frac{13!}{3!(10)!}

⇒ 13C_3 = \frac{13(12)(11)10!}{3(2)(1)(10)!}

⇒ 13C_3 = 13(2)(11)

⇒ 13 C_3 = 286

∴ Number of ways to select 3 books from 13 books for adoption is 286 .

3 0
3 years ago
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