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Bingel [31]
3 years ago
13

Michael invested 5,000 in an account that has a 5.5% annual interest rate. What equation best describes investment after T years

?
Mathematics
1 answer:
ivolga24 [154]3 years ago
5 0

Answer:

V = 5000 +  275*T   for simple annual interest

or:   A = 5000 * (1.055)^T   for an annual compound interest

Step-by-step explanation:

I assume this is a simple interest rate.  If not I will give the one for compound interest.

V = 5000 + 5000* 0.055 * T      (Value of account after T years)

V = 5000 +  275*T   for simple annual interest

or:   A = 5000 * (1.055)^T   for an annual compound interest

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A two digit number is chosen at random. funny the probability that the number is less than 20​
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3 years ago
Simultaneous equations 5x+y=28 x+y=2
ludmilkaskok [199]

Answer:

<h2>( \frac{13}{2}  \:,  -  \frac{9}{2} )</h2>

Step-by-step explanation:

5x + y = 28

x + y = 8

Solve the equation for y by moving 'x' to R.H.S and changing its sign

5x + y = 28

y = 2 - x

Substitute the given value of y into the equation 5x + y = 28

5x + 2 - x = 28

Solve the equation for x

Collect like terms

4x + 2 = 28

Move constant to R.H.S and change its sign

4x = 28 - 2

Subtract the numbers

4x  = 26

Divide both sides of the equation by 4

\frac{4x}{4}  =  \frac{26}{4}

Calculate

x =  \frac{26}{4}

Reduce the numbers with 2

x =  \frac{13}{2}

Now, substitute the given value of x into the equation y = 2 - x

y = 2 -  \frac{13}{2}

Solve the equation for y

y =  -  \frac{9}{2}

The possible solution of the system is the ordered pair ( x , y )

<h2>(x \: y) = ( \frac{13}{2} , \:  -  \frac{9}{2} )</h2>

-------------------------------------------------------------

Let's check if the given ordered pair is the solution of the system of equation:

plug the value of x and y in both equation

5 \times  \frac{13}{2}  -  \frac{9}{2}  = 28

\frac{13}{2}  -  \frac{9}{2}  = 2

Simplify the equalities

28 = 28

2 = 2

Since , all of the equalities are true, the ordered pair is the solution of the system.

(x  \:, y \: ) = ( \frac{13}{2}  \: , -  \frac{9}{2})

Hope this helps....

Best regards!!

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3 years ago
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