A 15.00 mL pipet. As a pipet is more accurate than a buret.
The formula is Mn2+CO2= MnCO3
Answer:
(b) BeF2 > OF2 > CH3OH
Explanation:
The degree and type of intermolecular forces present in a substance influences its vapour pressure considerably. The greater the magnitude and strength of intermolecular forces in the substance, the lower the vapour pressure of the substance.
BeF2 molecules are held together by weak vanderwaals forces hence BeF2 will exhibit the least degree of intermolecular interaction and have the highest vapour pressure. OF2 molecules are bound together by dipole interactions hence it will exhibit a lower vapour pressure compared to BeF2. CH3OH molecules form hydrogen bonds with water molecules hence it will exhibit the least vapour pressure among the trio.
Answer:
HI (aq) → H⁺ (aq) + I⁻ (aq)
HI (aq) + H₂O(l) → H₃O⁺ (aq) + I⁻ (aq)
Explanation:
The Arrhenius acid concept indicates that a substance behaves like acid if it produces hydrogen ions H⁺ or hydronium ions H₃O⁺ in water. A substance will be classified as a base if it produces OH⁻ hydroxide ions in water. This way of defining acids and bases works well for aqueous solutions.
When we mix HI (aq) and water, we are increasing [H₃O⁺]
HI (aq) → H⁺ (aq) + I⁻ (aq)
HI (aq) + H₂O(l) → H₃O⁺ (aq) + I⁻ (aq)
The array will be created with the elements equal to null.
