Ask question

Ask question

All categories

3 years ago

5

A gas at a constant temperature of 300. K, a pressure of 200. kPa, and a volume of 15.0L was decreased to a volume of 10.0 L. Wh

at is the new
pressure of the gas?

1 answer:

Vesnalui [34]3 years ago

3 0

Answer:

300 kPa

Explanation:

P2=P1V1/V2

You can check this by knowing that P and V at constant T have an inverse relationship. Hence, this is correct.

You might be interested in

You placed 43.1 g of an unknown metal at 100 °C into a coffee cup calorimeter that contained 50.0 g of water that was initially

nika2105 [10]

Answer :

(a) The heat released by the metal is -312.48 J

(b) The specific heat of the metal is $0.0944J/g^oC$

Explanation :

<u>For part A :</u>

Heat released by the metal = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the metal

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $51.5J/^oC$

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_2$ = mass of water = 50.0 g

$\Delta T$ = change in temperature = $(T_{final}-T_{initial})=23.2-22.0=1.2^oC$

Now put all the given values in the above formula, we get:

$q=[(51.5J/^oC\times 1.2^oC)+(50.0g\times 4.184J/g^oC\times 1.2^oC)]$

$q=312.48J$

Thus, the heat released by the metal is -312.48 J

<u>For part B :</u>

$q=m\times c\times \Delta T$

q = heat released by the metal = -312.48 J

m = mass of metal = 43.1 g

c = specific heat of metal = ?

$\Delta T$ = change in temperature = $(T_{final}-T_{initial})=23.2-100=76.8^oC$

Now put all the given values in the above formula, we get:

$-312.48J=43.1g\times c\times 76.8^oC$

$c=0.0944J/g^oC$

Thus, the specific heat of the metal is $0.0944J/g^oC$

8 0

4 years ago

Must new substances be formed when you observe a chemical property? explain

Yuliya22 [10]

Yes. Whenever a chemical change is observed (a few examples being change in color, odor, or precipitate formation) a new substance is formed.

7 0

4 years ago

Consider the reaction of ethyl acetate with sodium hydroxide: CH3COOC2H5(aq)+NaOH(aq)⇌CH3COONa(aq)+C2H5OH(aq) The reaction is fi

Alexus [3.1K]

Answer: The rate law is $rate=k[CH_3COOC_2H_5]^1[NaOH]^1$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

For the given reaction:

$CH_3COOC_2H_5(aq)+NaOH(aq)\rightleftharpoons CH_3COONa(aq)+C_2H_5OH(aq)$

k= rate constant

Rate law: $rate=k[CH_3COOC_2H_5]^x[NaOH]^y$

For the given rate law:

y =1 = order with respect to $NaOH$

n = total order = 2

2= (x+y)

2= (x+1)

x= 1

Thus order with respect to $CH_3COOC_2H_5$ is 1 and rate law is : $rate=k[CH_3COOC_2H_5]^1[NaOH]^1$

6 0

3 years ago

explain one or two things that adversely (negatively) affect the Earth's environment. How do you know that these things you're d

zimovet [89]

Answer:

Humans impact the physical environment in many ways: overpopulation, pollution, burning fossil fuels, and deforestation. Changes like these have triggered climate change, soil erosion, poor air quality, and undrinkable water.

8 0

3 years ago

Read 2 more answers

What is the condensed structural formula of the product of the reaction of 2,7-dimethyl-4-octene with hydrogen and a metal catal

gavmur [86]

The condensed structural formula of the product of the reaction of 2,7-dimethyl-4-octene with hydrogen and metal catalyst.

Ch3 CH(CH3) CH2 CH2 CH2 CH2 CH(CH3) CH3

Equation is as follows

CH3 CH(CH3) CH2 C=C CH2 CH(CH3) CH3 + H2→

CH3 CH(CH3)CH2 CH2 CH2 CH2 CH(CH3) CH3

metal catalyst example is nickel and the name of structure formed is
2,7- dimethyl octane

6 0

4 years ago