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adoni [48]
1 year ago
10

the application you attempted to authenticate to is not authorized to use cas. contact your cas administrator to learn how you m

ight register and integrate your application with cas.
Computers and Technology
1 answer:
bogdanovich [222]1 year ago
7 0

If you're seeing this error message, it means that the application you're trying to authenticate with is not authorized to use CAS. CAS is a Central Authentication Service that allows applications to securely authenticate users.

If you're the administrator of the application in question, you'll need to register and integrate your application with CAS. This process is usually pretty straightforward, and there are plenty of resources available to help you get started.

If you're not the administrator, you'll need to contact the CAS administrator to resolve the issue. In most cases, they'll be able to help you get set up with the necessary credentials.

Learn more on CAS here:

brainly.com/question/26986135

#SPJ4

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which of these tools stick to the edge of an image, thus making it easy to select the shape of an image
USPshnik [31]

Answer:

ljb lih lug outbpiyougvotvoy

outiyfiyfiyfiyffiyvitfurcutfcutcrcutfutcdu

Explanation:

didn't understand the question

3 0
3 years ago
Write a c program that reprints input so that no line is longer than 50 characters. Specifically, for lines less than or equal t
Alex73 [517]

Using the knowledge in computational language in C++ it is possible to write a code that reprints prints input so that no line is longer than 50 characters.

<h3>Writting the code:</h3>

<em>#include<stdio.h></em>

<em />

<em>int main(int argc, char** argv){</em>

<em>    //creating pointer to read a file</em>

<em>    FILE * fp;</em>

<em>    char * line = NULL;</em>

<em>    size_t len = 0;</em>

<em>    ssize_t read;</em>

<em>    int i=0;</em>

<em>    //opening a file</em>

<em>    fp = fopen(argv[1], "r");</em>

<em>    //handling the error condition</em>

<em>    if (fp == NULL){</em>

<em>        printf("File not found..!!");</em>

<em>        return 0;</em>

<em>    }</em>

<em>    int moreThan50 =0;</em>

<em>    //reading a file line by line</em>

<em>    while ((read = getline(&line, &len, fp)) != -1) {</em>

<em>        i = 0;</em>

<em>        if(read >= 50){</em>

<em>            moreThan50++;</em>

<em>        }</em>

<em>        while(i < read){</em>

<em>            if(line[i]!='\n'){</em>

<em>                if(i%50 == 0){</em>

<em>                    printf("\n%c",line[i]);</em>

<em>                }else{</em>

<em>                    printf("%c",line[i]);</em>

<em>                }</em>

<em>            }</em>

<em>            i++;</em>

<em>        }</em>

<em>    }</em>

<em>    printf("\nTotal lines over 50 chars: %d\n",moreThan50);</em>

<em>    printf("Offending Lines: ");</em>

<em>    for(i=1;i<=moreThan50;i++)</em>

<em>        printf("%d, ",i);</em>

<em>    fclose(fp);</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

4 0
2 years ago
Hexadecimal to denary gcse method
Anuta_ua [19.1K]

There are two ways to convert from hexadecimal to denary gcse method. They are:

  • Conversion from hex to denary via binary.
  • The use of base 16 place-value columns.

<h3>How is the conversion done?</h3>

In Conversion from hex to denary via binary:

One has to Separate the hex digits to be able to know or find its equivalent in binary, and then the person will then put them back together.

Example - Find out the denary value of hex value 2D.

It will be:

2 = 0010

D = 1101

Put them them together and then you will have:

00101101

Which is known to be:

0 *128 + 0 * 64 + 1 *32 + 0 * 16 + 1 *8 + 1 *4 + 0 *2 + 1 *1

= 45 in denary form.

Learn more about hexadecimal from

brainly.com/question/11109762

#SPJ1

3 0
2 years ago
Given the String variables name1 and name2, write a fragment of code that assigns the larger of the two to the variable first (a
Neporo4naja [7]

Answer:

if ( name1 > name2) {

    first = name1;

} else {

    first = name2;

}

Explanation:

First you need take a decision for that reason you need and if - else structure to decide if asign the variable name1 or the variable name2 to the result. Later you can use an > or < to compare two strings because it use the ASCII code to compare wich one is larger than another.

if ( name1 > name2) {

    first = name1;

} else {

    first = name2;

}

6 0
3 years ago
What HTML tag would you use to indicate a line break?
DIA [1.3K]

Answer:

<br> APEX Verified

Explanation:

8 0
3 years ago
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